You are given a 0-indexed integer array costs where costs[i] is the cost of hiring the ith worker.
You are also given two integers k and candidates. We want to hire exactly k workers according to the following rules:
k sessions and hire exactly one worker in each session.candidates workers or the last candidates workers. Break the tie by the smallest index.\n\tcosts = [3,2,7,7,1,2] and candidates = 2, then in the first hiring session, we will choose the 4th worker because they have the lowest cost [3,2,7,7,1,2].1st worker because they have the same lowest cost as 4th worker but they have the smallest index [3,2,7,7,2]. Please note that the indexing may be changed in the process.Return the total cost to hire exactly k workers.
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Example 1:
\n\n\nInput: costs = [17,12,10,2,7,2,11,20,8], k = 3, candidates = 4\nOutput: 11\nExplanation: We hire 3 workers in total. The total cost is initially 0.\n- In the first hiring round we choose the worker from [17,12,10,2,7,2,11,20,8]. The lowest cost is 2, and we break the tie by the smallest index, which is 3. The total cost = 0 + 2 = 2.\n- In the second hiring round we choose the worker from [17,12,10,7,2,11,20,8]. The lowest cost is 2 (index 4). The total cost = 2 + 2 = 4.\n- In the third hiring round we choose the worker from [17,12,10,7,11,20,8]. The lowest cost is 7 (index 3). The total cost = 4 + 7 = 11. Notice that the worker with index 3 was common in the first and last four workers.\nThe total hiring cost is 11.\n\n\n
Example 2:
\n\n\nInput: costs = [1,2,4,1], k = 3, candidates = 3\nOutput: 4\nExplanation: We hire 3 workers in total. The total cost is initially 0.\n- In the first hiring round we choose the worker from [1,2,4,1]. The lowest cost is 1, and we break the tie by the smallest index, which is 0. The total cost = 0 + 1 = 1. Notice that workers with index 1 and 2 are common in the first and last 3 workers.\n- In the second hiring round we choose the worker from [2,4,1]. The lowest cost is 1 (index 2). The total cost = 1 + 1 = 2.\n- In the third hiring round there are less than three candidates. We choose the worker from the remaining workers [2,4]. The lowest cost is 2 (index 0). The total cost = 2 + 2 = 4.\nThe total hiring cost is 4.\n\n\n
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Constraints:
\n\n1 <= costs.length <= 105 1 <= costs[i] <= 1051 <= k, candidates <= costs.length给你一个下标从 0 开始的整数数组 costs ，其中 costs[i] 是雇佣第 i 位工人的代价。
同时给你两个整数 k 和 candidates 。我们想根据以下规则恰好雇佣 k 位工人：
k 轮雇佣，且每一轮恰好雇佣一位工人。candidates 和最后面 candidates 人中选出代价最小的一位工人，如果有多位代价相同且最小的工人，选择下标更小的一位工人。\n\tcosts = [3,2,7,7,1,2] 且 candidates = 2 ，第一轮雇佣中，我们选择第 4 位工人，因为他的代价最小 [3,2,7,7,1,2] 。1 位工人，因为他们的代价与第 4 位工人一样都是最小代价，而且下标更小，[3,2,7,7,2] 。注意每一轮雇佣后，剩余工人的下标可能会发生变化。candidates 人，那么下一轮雇佣他们中代价最小的一人，如果有多位代价相同且最小的工人，选择下标更小的一位工人。返回雇佣恰好 k 位工人的总代价。
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示例 1：
\n\n输入：costs = [17,12,10,2,7,2,11,20,8], k = 3, candidates = 4\n输出：11\n解释：我们总共雇佣 3 位工人。总代价一开始为 0 。\n- 第一轮雇佣，我们从 [17,12,10,2,7,2,11,20,8] 中选择。最小代价是 2 ，有两位工人，我们选择下标更小的一位工人，即第 3 位工人。总代价是 0 + 2 = 2 。\n- 第二轮雇佣，我们从 [17,12,10,7,2,11,20,8] 中选择。最小代价是 2 ，下标为 4 ，总代价是 2 + 2 = 4 。\n- 第三轮雇佣，我们从 [17,12,10,7,11,20,8] 中选择，最小代价是 7 ，下标为 3 ，总代价是 4 + 7 = 11 。注意下标为 3 的工人同时在最前面和最后面 4 位工人中。\n总雇佣代价是 11 。\n\n\n
示例 2：
\n\n输入：costs = [1,2,4,1], k = 3, candidates = 3\n输出：4\n解释：我们总共雇佣 3 位工人。总代价一开始为 0 。\n- 第一轮雇佣，我们从 [1,2,4,1] 中选择。最小代价为 1 ，有两位工人，我们选择下标更小的一位工人，即第 0 位工人，总代价是 0 + 1 = 1 。注意，下标为 1 和 2 的工人同时在最前面和最后面 3 位工人中。\n- 第二轮雇佣，我们从 [2,4,1] 中选择。最小代价为 1 ，下标为 2 ，总代价是 1 + 1 = 2 。\n- 第三轮雇佣，少于 3 位工人，我们从剩余工人 [2,4] 中选择。最小代价是 2 ，下标为 0 。总代价为 2 + 2 = 4 。\n总雇佣代价是 4 。\n\n\n
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提示：
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