{ "data": { "question": { "questionId": "443", "questionFrontendId": "443", "categoryTitle": "Algorithms", "boundTopicId": 1325, "title": "String Compression", "titleSlug": "string-compression", "content": "
Given an array of characters chars
, compress it using the following algorithm:
Begin with an empty string s
. For each group of consecutive repeating characters in chars
:
1
, append the character to s
.The compressed string s
should not be returned separately, but instead, be stored in the input character array chars
. Note that group lengths that are 10
or longer will be split into multiple characters in chars
.
After you are done modifying the input array, return the new length of the array.
\n\nYou must write an algorithm that uses only constant extra space.
\n\n\n
Example 1:
\n\n\nInput: chars = ["a","a","b","b","c","c","c"]\nOutput: Return 6, and the first 6 characters of the input array should be: ["a","2","b","2","c","3"]\nExplanation: The groups are "aa", "bb", and "ccc". This compresses to "a2b2c3".\n\n\n
Example 2:
\n\n\nInput: chars = ["a"]\nOutput: Return 1, and the first character of the input array should be: ["a"]\nExplanation: The only group is "a", which remains uncompressed since it's a single character.\n\n\n
Example 3:
\n\n\nInput: chars = ["a","b","b","b","b","b","b","b","b","b","b","b","b"]\nOutput: Return 4, and the first 4 characters of the input array should be: ["a","b","1","2"].\nExplanation: The groups are "a" and "bbbbbbbbbbbb". This compresses to "ab12".\n\n
\n
Constraints:
\n\n1 <= chars.length <= 2000
chars[i]
is a lowercase English letter, uppercase English letter, digit, or symbol.给你一个字符数组 chars
,请使用下述算法压缩:
从一个空字符串 s
开始。对于 chars
中的每组 连续重复字符 :
1
,则将字符追加到 s
中。s
追加字符,后跟这一组的长度。压缩后得到的字符串 s
不应该直接返回 ,需要转储到字符数组 chars
中。需要注意的是,如果组长度为 10
或 10
以上,则在 chars
数组中会被拆分为多个字符。
请在 修改完输入数组后 ,返回该数组的新长度。
\n\n你必须设计并实现一个只使用常量额外空间的算法来解决此问题。
\n\n\n\n
示例 1:
\n\n\n输入:chars = [\"a\",\"a\",\"b\",\"b\",\"c\",\"c\",\"c\"]\n输出:返回 6 ,输入数组的前 6 个字符应该是:[\"a\",\"2\",\"b\",\"2\",\"c\",\"3\"]\n解释:\"aa\" 被 \"a2\" 替代。\"bb\" 被 \"b2\" 替代。\"ccc\" 被 \"c3\" 替代。\n\n\n
示例 2:
\n\n\n输入:chars = [\"a\"]\n输出:返回 1 ,输入数组的前 1 个字符应该是:[\"a\"]\n解释:唯一的组是“a”,它保持未压缩,因为它是一个字符。\n\n\n
示例 3:
\n\n\n输入:chars = [\"a\",\"b\",\"b\",\"b\",\"b\",\"b\",\"b\",\"b\",\"b\",\"b\",\"b\",\"b\",\"b\"]\n输出:返回 4 ,输入数组的前 4 个字符应该是:[\"a\",\"b\",\"1\",\"2\"]。\n解释:由于字符 \"a\" 不重复,所以不会被压缩。\"bbbbbbbbbbbb\" 被 “b12” 替代。\n\n\n
\n\n
提示:
\n\n1 <= chars.length <= 2000
chars[i]
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use-after-free<\\/code>\\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n
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Python 2.7.12<\\/code><\\/p>\\r\\n\\r\\n
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out-of-bounds<\\/code>\\u548c
use-after-free<\\/code>\\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n
\\r\\nstruct hash_entry {\\r\\n int id; \\/* we'll use this field as the key *\\/\\r\\n char name[10];\\r\\n UT_hash_handle hh; \\/* makes this structure hashable *\\/\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = NULL;\\r\\n\\r\\nvoid add_user(struct hash_entry *s) {\\r\\n HASH_ADD_INT(users, id, s);\\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\\r\\n\\r\\n
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