{ "data": { "question": { "questionId": "1653", "questionFrontendId": "1530", "categoryTitle": "Algorithms", "boundTopicId": 343649, "title": "Number of Good Leaf Nodes Pairs", "titleSlug": "number-of-good-leaf-nodes-pairs", "content": "

You are given the root of a binary tree and an integer distance. A pair of two different leaf nodes of a binary tree is said to be good if the length of the shortest path between them is less than or equal to distance.

\n\n

Return the number of good leaf node pairs in the tree.

\n\n

 

\n

Example 1:

\n\"\"\n
\nInput: root = [1,2,3,null,4], distance = 3\nOutput: 1\nExplanation: The leaf nodes of the tree are 3 and 4 and the length of the shortest path between them is 3. This is the only good pair.\n
\n\n

Example 2:

\n\"\"\n
\nInput: root = [1,2,3,4,5,6,7], distance = 3\nOutput: 2\nExplanation: The good pairs are [4,5] and [6,7] with shortest path = 2. The pair [4,6] is not good because the length of ther shortest path between them is 4.\n
\n\n

Example 3:

\n\n
\nInput: root = [7,1,4,6,null,5,3,null,null,null,null,null,2], distance = 3\nOutput: 1\nExplanation: The only good pair is [2,5].\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "好叶子节点对的数量", "translatedContent": "

给你二叉树的根节点 root 和一个整数 distance 。

\n\n

如果二叉树中两个 叶 节点之间的 最短路径长度 小于或者等于 distance ，那它们就可以构成一组 好叶子节点对 。

\n\n

返回树中 好叶子节点对的数量 。

\n\n

 

\n\n

示例 1：

\n\n

 

\n\n

\"\"

\n\n
输入：root = [1,2,3,null,4], distance = 3\n输出：1\n解释：树的叶节点是 3 和 4 ，它们之间的最短路径的长度是 3 。这是唯一的好叶子节点对。\n
\n\n

示例 2：

\n\n

\"\"

\n\n
输入：root = [1,2,3,4,5,6,7], distance = 3\n输出：2\n解释：好叶子节点对为 [4,5] 和 [6,7] ，最短路径长度都是 2 。但是叶子节点对 [4,6] 不满足要求，因为它们之间的最短路径长度为 4 。\n
\n\n

示例 3：

\n\n
输入：root = [7,1,4,6,null,5,3,null,null,null,null,null,2], distance = 3\n输出：1\n解释：唯一的好叶子节点对是 [2,5] 。\n
\n\n

示例 4：

\n\n
输入：root = [100], distance = 1\n输出：0\n
\n\n

示例 5：

\n\n
输入：root = [1,1,1], distance = 2\n输出：1\n
\n\n

 

\n\n

提示：

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0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @param {number} distance\n * @return {number}\n */\nvar countPairs = function(root, distance) {\n\n};", "__typename": "CodeSnippetNode" }, { "lang": "Ruby", "langSlug": "ruby", "code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @param {Integer} distance\n# @return {Integer}\ndef count_pairs(root, distance)\n\nend", "__typename": "CodeSnippetNode" }, { "lang": "Swift", "langSlug": "swift", "code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func countPairs(_ root: TreeNode?, _ distance: Int) -> Int {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Go", "langSlug": "golang", "code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc countPairs(root *TreeNode, distance int) int {\n\n}", "__typename": "CodeSnippetNode" }, { "lang": "Scala", "langSlug": "scala", "code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def countPairs(root: TreeNode, distance: Int): Int = {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Kotlin", "langSlug": "kotlin", "code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun countPairs(root: TreeNode?, distance: Int): Int {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Rust", "langSlug": "rust", "code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option>>,\n// pub right: Option>>,\n// }\n//\n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn count_pairs(root: Option>>, distance: i32) -> i32 {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "PHP", "langSlug": "php", "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @param Integer $distance\n * @return Integer\n */\n function countPairs($root, $distance) {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "TypeScript", "langSlug": "typescript", "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction countPairs(root: TreeNode | null, distance: number): number {\n\n};", "__typename": "CodeSnippetNode" }, { "lang": "Racket", "langSlug": "racket", "code": "; Definition for a binary tree node.\n#|\n\n; val : integer?\n; left : (or/c tree-node? #f)\n; right : (or/c tree-node? #f)\n(struct tree-node\n (val left right) #:mutable #:transparent)\n\n; constructor\n(define (make-tree-node [val 0])\n (tree-node val #f #f))\n\n|#\n\n(define/contract (count-pairs root distance)\n (-> (or/c tree-node? #f) exact-integer? exact-integer?)\n\n )", "__typename": "CodeSnippetNode" }, { "lang": "Erlang", "langSlug": "erlang", "code": "%% Definition for a binary tree node.\n%%\n%% -record(tree_node, {val = 0 :: integer(),\n%% left = null :: 'null' | #tree_node{},\n%% right = null :: 'null' | #tree_node{}}).\n\n-spec count_pairs(Root :: #tree_node{} | null, Distance :: integer()) -> integer().\ncount_pairs(Root, Distance) ->\n .", "__typename": "CodeSnippetNode" }, { "lang": "Elixir", "langSlug": "elixir", "code": "# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# left: TreeNode.t() | nil,\n# right: TreeNode.t() | nil\n# }\n# defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule Solution do\n @spec count_pairs(root :: TreeNode.t | nil, distance :: integer) :: integer\n def count_pairs(root, distance) do\n\n end\nend", "__typename": "CodeSnippetNode" } ], "stats": "{\"totalAccepted\": \"9.7K\", \"totalSubmission\": \"16.8K\", \"totalAcceptedRaw\": 9690, \"totalSubmissionRaw\": 16845, \"acRate\": \"57.5%\"}", "hints": [ "Start DFS from each leaf node. stop the DFS when the number of steps done > distance.", "If you reach another leaf node within distance steps, add 1 to the answer.", "Note that all pairs will be counted twice so divide the answer by 2." ], "solution": null, "status": null, "sampleTestCase": "[1,2,3,null,4]\n3", "metaData": "{\n \"name\": \"countPairs\",\n \"params\": [\n {\n \"name\": \"root\",\n \"type\": \"TreeNode\"\n },\n {\n \"type\": \"integer\",\n \"name\": \"distance\"\n }\n ],\n \"return\": {\n \"type\": \"integer\"\n }\n}", "judgerAvailable": true, "judgeType": "large", "mysqlSchemas": [], "enableRunCode": true, "envInfo": "{\"cpp\":[\"C++\",\"

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Racket CS<\\/a> v8.3<\\/p>\\r\\n\\r\\n
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