{ "data": { "question": { "questionId": "525", "questionFrontendId": "525", "categoryTitle": "Algorithms", "boundTopicId": 1910, "title": "Contiguous Array", "titleSlug": "contiguous-array", "content": "
Given a binary array nums
, return the maximum length of a contiguous subarray with an equal number of 0
and 1
.
\n
Example 1:
\n\n\nInput: nums = [0,1]\nOutput: 2\nExplanation: [0, 1] is the longest contiguous subarray with an equal number of 0 and 1.\n\n\n
Example 2:
\n\n\nInput: nums = [0,1,0]\nOutput: 2\nExplanation: [0, 1] (or [1, 0]) is a longest contiguous subarray with equal number of 0 and 1.\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 105
nums[i]
is either 0
or 1
.给定一个二进制数组 nums
, 找到含有相同数量的 0
和 1
的最长连续子数组,并返回该子数组的长度。
\n\n
示例 1:
\n\n\n输入: nums = [0,1]\n输出: 2\n说明: [0, 1] 是具有相同数量 0 和 1 的最长连续子数组。\n\n
示例 2:
\n\n\n输入: nums = [0,1,0]\n输出: 2\n说明: [0, 1] (或 [1, 0]) 是具有相同数量0和1的最长连续子数组。\n\n
\n\n
提示:
\n\n1 <= nums.length <= 105
nums[i]
不是 0
就是 1
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