{ "data": { "question": { "questionId": "955", "questionFrontendId": "919", "categoryTitle": "Algorithms", "boundTopicId": 1975, "title": "Complete Binary Tree Inserter", "titleSlug": "complete-binary-tree-inserter", "content": "
A complete binary tree is a binary tree in which every level, except possibly the last, is completely filled, and all nodes are as far left as possible.
\n\nDesign an algorithm to insert a new node to a complete binary tree keeping it complete after the insertion.
\n\nImplement the CBTInserter
class:
CBTInserter(TreeNode root)
Initializes the data structure with the root
of the complete binary tree.int insert(int v)
Inserts a TreeNode
into the tree with value Node.val == val
so that the tree remains complete, and returns the value of the parent of the inserted TreeNode
.TreeNode get_root()
Returns the root node of the tree.\n
Example 1:
\n\n\nInput\n["CBTInserter", "insert", "insert", "get_root"]\n[[[1, 2]], [3], [4], []]\nOutput\n[null, 1, 2, [1, 2, 3, 4]]\n\nExplanation\nCBTInserter cBTInserter = new CBTInserter([1, 2]);\ncBTInserter.insert(3); // return 1\ncBTInserter.insert(4); // return 2\ncBTInserter.get_root(); // return [1, 2, 3, 4]\n\n\n
\n
Constraints:
\n\n[1, 1000]
.0 <= Node.val <= 5000
root
is a complete binary tree.0 <= val <= 5000
104
calls will be made to insert
and get_root
.完全二叉树 是每一层(除最后一层外)都是完全填充(即,节点数达到最大)的,并且所有的节点都尽可能地集中在左侧。
\n\n设计一种算法,将一个新节点插入到一个完整的二叉树中,并在插入后保持其完整。
\n\n实现 CBTInserter
类:
CBTInserter(TreeNode root)
使用头节点为 root
的给定树初始化该数据结构;CBTInserter.insert(int v)
向树中插入一个值为 Node.val == val
的新节点 TreeNode
。使树保持完全二叉树的状态,并返回插入节点 TreeNode
的父节点的值;CBTInserter.get_root()
将返回树的头节点。\n\n
示例 1:
\n\n\n\n\n输入\n[\"CBTInserter\", \"insert\", \"insert\", \"get_root\"]\n[[[1, 2]], [3], [4], []]\n输出\n[null, 1, 2, [1, 2, 3, 4]]\n\n解释\nCBTInserter cBTInserter = new CBTInserter([1, 2]);\ncBTInserter.insert(3); // 返回 1\ncBTInserter.insert(4); // 返回 2\ncBTInserter.get_root(); // 返回 [1, 2, 3, 4]\n\n
\n\n
提示:
\n\n[1, 1000]
0 <= Node.val <= 5000
root
是完全二叉树0 <= val <= 5000
insert
和 get_root
操作 104
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