There exists an undirected tree with n nodes numbered 0 to n - 1. You are given a 2D integer array edges of length n - 1, where edges[i] = [ui, vi] indicates that there is an edge between nodes ui and vi in the tree.
Initially, all nodes are unmarked. For each node i:
i is odd, the node will get marked at time x if there is at least one node adjacent to it which was marked at time x - 1.i is even, the node will get marked at time x if there is at least one node adjacent to it which was marked at time x - 2.Return an array times where times[i] is the time when all nodes get marked in the tree, if you mark node i at time t = 0.
Note that the answer for each times[i] is independent, i.e. when you mark node i all other nodes are unmarked.
\n
Example 1:
\n\nInput: edges = [[0,1],[0,2]]
\n\nOutput: [2,4,3]
\n\nExplanation:
\n\n![\"\"](\"https://assets.leetcode.com/uploads/2024/06/01/screenshot-2024-06-02-122236.png\")
i = 0:\n\n\tt = 1, and Node 2 at t = 2.i = 1:\n\tt = 2, and Node 2 at t = 4.i = 2:\n\tt = 2, and Node 1 at t = 3.Example 2:
\n\nInput: edges = [[0,1]]
\n\nOutput: [1,2]
\n\nExplanation:
\n\n![\"\"](\"https://assets.leetcode.com/uploads/2024/06/01/screenshot-2024-06-02-122249.png\")
i = 0:\n\n\tt = 1.i = 1:\n\tt = 2.Example 3:
\n\nInput: edges = [[2,4],[0,1],[2,3],[0,2]]
\n\nOutput: [4,6,3,5,5]
\n\nExplanation:
\n\n![\"\"](\"https://assets.leetcode.com/uploads/2024/06/03/screenshot-2024-06-03-210550.png\")
\n
Constraints:
\n\n2 <= n <= 105edges.length == n - 1edges[i].length == 20 <= edges[i][0], edges[i][1] <= n - 1edges represents a valid tree.Compiled with clang 17 using the latest C++ 23 standard, and libstdc++ provided by GCC 13.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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