Alice and Bob are playing a game on a string.
\n\nYou are given a string s, Alice and Bob will take turns playing the following game where Alice starts first:
s that contains an odd number of vowels.s that contains an even number of vowels.The first player who cannot make a move on their turn loses the game. We assume that both Alice and Bob play optimally.
\n\nReturn true if Alice wins the game, and false otherwise.
The English vowels are: a, e, i, o, and u.
\n
Example 1:
\n\nInput: s = "leetcoder"
\n\nOutput: true
\n\nExplanation:
\nAlice can win the game as follows:
s = "leetcoder" which contains 3 vowels. The resulting string is s = "der".s = "der" which contains 0 vowels. The resulting string is s = "er".s = "er" which contains 1 vowel.Example 2:
\n\nInput: s = "bbcd"
\n\nOutput: false
\n\nExplanation:
\nThere is no valid play for Alice in her first turn, so Alice loses the game.
\n
Constraints:
\n\n1 <= s.length <= 105s consists only of lowercase English letters.小红和小明在玩一个字符串元音游戏。
\n\n给你一个字符串 s，小红和小明将轮流参与游戏，小红 先 开始：
s 中包含 奇数 个元音的任意 非空 子字符串。s 中包含 偶数 个元音的任意 非空 子字符串。第一个无法在其回合内进行移除操作的玩家输掉游戏。假设小红和小明都采取 最优策略 。
\n\n如果小红赢得游戏，返回 true，否则返回 false。
英文元音字母包括：a, e, i, o, 和 u。
\n\n
示例 1：
\n\n输入： s = \"leetcoder\"
\n\n输出： true
\n\n解释：
\n小红可以执行如下移除操作来赢得游戏：
s = \"leetcoder\"，其中包含 3 个元音。结果字符串为 s = \"der\"。s = \"der\"，其中包含 0 个元音。结果字符串为 s = \"er\"。s = \"er\"，其中包含 1 个元音。示例 2：
\n\n输入： s = \"bbcd\"
\n\n输出： false
\n\n解释：
\n小红在她的第一回合无法执行移除操作，因此小红输掉了游戏。
\n\n
提示：
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collections<\\/a>\\u3002\\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u6ce8\\u610f Python 2.7 \\u5c06\\u57282020\\u5e74\\u540e\\u4e0d\\u518d\\u7ef4\\u62a4<\\/a>\\u3002 \\u5982\\u60f3\\u4f7f\\u7528\\u6700\\u65b0\\u7248\\u7684Python\\uff0c\\u8bf7\\u9009\\u62e9Python 3\\u3002<\\/p>\"],\"c\":[\"C\",\" \\u7248\\u672c\\uff1a \\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528 \\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u5982\\u60f3\\u4f7f\\u7528\\u54c8\\u5e0c\\u8868\\u8fd0\\u7b97, \\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 uthash<\\/a>\\u3002 \\\"uthash.h\\\"\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5bfc\\u5165\\u3002\\u8bf7\\u770b\\u5982\\u4e0b\\u793a\\u4f8b:<\\/p>\\r\\n\\r\\n 1. 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\\u6a21\\u5757\\u4e2d\\u63d0\\u4f9b\\uff1ahttps:\\/\\/www.rubydoc.info\\/github\\/kanwei\\/algorithms\\/Algorithms<\\/p>\"],\"swift\":[\"Swift\",\" \\u7248\\u672c\\uff1a \\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 swift-algorithms 1.2.0<\\/a> \\u548c swift-collections 1.1.0<\\/a><\\/p>\\r\\n\\r\\n \\u6211\\u4eec\\u901a\\u5e38\\u4fdd\\u8bc1\\u66f4\\u65b0\\u5230 Apple\\u653e\\u51fa\\u7684\\u6700\\u65b0\\u7248Swift<\\/a>\\u3002\\u5982\\u679c\\u60a8\\u53d1\\u73b0Swift\\u4e0d\\u662f\\u6700\\u65b0\\u7248\\u7684\\uff0c\\u8bf7\\u8054\\u7cfb\\u6211\\u4eec\\uff01\\u6211\\u4eec\\u5c06\\u5c3d\\u5feb\\u66f4\\u65b0\\u3002<\\/p>\"],\"golang\":[\"Go\",\" \\u7248\\u672c\\uff1a \\u652f\\u6301 https:\\/\\/pkg.go.dev\\/github.com\\/emirpasic\\/gods@v1.18.1<\\/a> \\u548c https:\\/\\/pkg.go.dev\\/github.com\\/emirpasic\\/gods\\/v2@v2.0.0-alpha<\\/a> \\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\" \\u7248\\u672c\\uff1a 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"book": null,
"isSubscribed": false,
"isDailyQuestion": false,
"dailyRecordStatus": null,
"editorType": "CKEDITOR",
"ugcQuestionId": null,
"style": "LEETCODE",
"exampleTestcases": "\"leetcoder\"\n\"bbcd\"",
"__typename": "QuestionNode"
}
}
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