You are given an array of integers nums. Some values in nums are missing and are denoted by -1.
You can choose a pair of positive integers (x, y) exactly once and replace each missing element with either x or y.
You need to minimize the maximum absolute difference between adjacent elements of nums after replacements.
Return the minimum possible difference.
\n\n\n
Example 1:
\n\nInput: nums = [1,2,-1,10,8]
\n\nOutput: 4
\n\nExplanation:
\n\nBy choosing the pair as (6, 7), nums can be changed to [1, 2, 6, 10, 8].
The absolute differences between adjacent elements are:
\n\n|1 - 2| == 1|2 - 6| == 4|6 - 10| == 4|10 - 8| == 2Example 2:
\n\nInput: nums = [-1,-1,-1]
\n\nOutput: 0
\n\nExplanation:
\n\nBy choosing the pair as (4, 4), nums can be changed to [4, 4, 4].
Example 3:
\n\nInput: nums = [-1,10,-1,8]
\n\nOutput: 1
\n\nExplanation:
\n\nBy choosing the pair as (11, 9), nums can be changed to [11, 10, 9, 8].
\n
Constraints:
\n\n2 <= nums.length <= 105nums[i] is either -1 or in the range [1, 109].给你一个整数数组 nums 。nums 中的一些值 缺失 了，缺失的元素标记为 -1 。
你需要选择 一个正 整数数对 (x, y) ，并将 nums 中每一个 缺失 元素用 x 或者 y 替换。
你的任务是替换 nums 中的所有缺失元素，最小化 替换后数组中相邻元素 绝对差值 的 最大值 。
请你返回上述要求下的 最小值 。
\n\n\n\n
示例 1：
\n\n输入：nums = [1,2,-1,10,8]
\n\n输出：4
\n\n解释：
\n\n选择数对 (6, 7) ，nums 变为 [1, 2, 6, 10, 8] 。
相邻元素的绝对差值分别为：
\n\n|1 - 2| == 1|2 - 6| == 4|6 - 10| == 4|10 - 8| == 2示例 2：
\n\n输入：nums = [-1,-1,-1]
\n\n输出：0
\n\n解释：
\n\n选择数对 (4, 4) ，nums 变为 [4, 4, 4] 。
示例 3：
\n\n输入：nums = [-1,10,-1,8]
\n\n输出：1
\n\n解释：
\n\n选择数对 (11, 9) ，nums 变为 [11, 10, 9, 8] 。
\n\n
提示：
\n\n2 <= nums.length <= 105nums[i] 要么是 -1 ，要么是范围 [1, 109] 中的一个整数。d, it can be proved that for the optimal case we'll replace -1s with values 0 < x <= y and it's always optimal to select x = min(a) + d. So we only need to select y.",
"Binary search on d."
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