Given a string s containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid.
An input string is valid if:
\n\n\n
Example 1:
\n\n\nInput: s = "()"\nOutput: true\n\n\n
Example 2:
\n\n\nInput: s = "()[]{}"\nOutput: true\n\n\nExample 3:
\n\n\nInput: s = "(]"\nOutput: false\n\n\n
\n
Constraints:
\n\n1 <= s.length <= 104s consists of parentheses only '()[]{}'.给定一个只包括 '('，')'，'{'，'}'，'['，']' 的字符串 s ，判断字符串是否有效。
有效字符串需满足：
\n\n\n\n
示例 1：
\n\n\n输入：s = \"()\"\n输出：true\n\n\n
示例 2：
\n\n\n输入：s = \"()[]{}\"\n输出：true\n\n\n示例 3：
\n\n\n输入：s = \"(]\"\n输出：false\n\n\n
示例 4：
\n\n\n输入：s = \"([)]\"\n输出：false\n\n\n
示例 5：
\n\n\n输入：s = \"{[]}\"\n输出：true\n\n\n\n
提示：
\n\n1 <= s.length <= 104s 仅由括号 '()[]{}' 组成\r\n{ { } [ ] [ [ [ ] ] ] } is VALID expression\r\n [ [ [ ] ] ] is VALID sub-expression\r\n { } [ ] is VALID sub-expression\r\n\r\n\r\nCan we exploit this recursive structure somehow?",
"What if whenever we encounter a matching pair of parenthesis in the expression, we simply remove it from the expression? This would keep on shortening the expression. e.g.\r\n\r\n\r\n{ { ( { } ) } }\r\n |_|\r\n\r\n{ { ( ) } }\r\n |______|\r\n\r\n{ { } }\r\n |__________|\r\n\r\n{ }\r\n|________________|\r\n\r\nVALID EXPRESSION!\r\n",
"The stack data structure can come in handy here in representing this recursive structure of the problem. We can't really process this from the inside out because we don't have an idea about the overall structure. But, the stack can help us process this recursively i.e. from outside to inwards."
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