{ "data": { "question": { "questionId": "1121", "questionFrontendId": "1043", "categoryTitle": "Algorithms", "boundTopicId": 4577, "title": "Partition Array for Maximum Sum", "titleSlug": "partition-array-for-maximum-sum", "content": "

Given an integer array arr, partition the array into (contiguous) subarrays of length at most k. After partitioning, each subarray has their values changed to become the maximum value of that subarray.

\n\n

Return the largest sum of the given array after partitioning. Test cases are generated so that the answer fits in a 32-bit integer.

\n\n

 

\n

Example 1:

\n\n
\nInput: arr = [1,15,7,9,2,5,10], k = 3\nOutput: 84\nExplanation: arr becomes [15,15,15,9,10,10,10]\n
\n\n

Example 2:

\n\n
\nInput: arr = [1,4,1,5,7,3,6,1,9,9,3], k = 4\nOutput: 83\n
\n\n

Example 3:

\n\n
\nInput: arr = [1], k = 1\nOutput: 1\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "分隔数组以得到最大和", "translatedContent": "

给你一个整数数组 arr，请你将该数组分隔为长度最多为 k 的一些（连续）子数组。分隔完成后，每个子数组的中的所有值都会变为该子数组中的最大值。

\n\n

返回将数组分隔变换后能够得到的元素最大和。

\n\n

 

\n\n

注意，原数组和分隔后的数组对应顺序应当一致，也就是说，你只能选择分隔数组的位置而不能调整数组中的顺序。

\n\n

 

\n\n

示例 1：

\n\n
\n输入：arr = [1,15,7,9,2,5,10], k = 3\n输出：84\n解释：\n因为 k=3 可以分隔成 [1,15,7] [9] [2,5,10]，结果为 [15,15,15,9,10,10,10]，和为 84，是该数组所有分隔变换后元素总和最大的。\n若是分隔成 [1] [15,7,9] [2,5,10]，结果就是 [1, 15, 15, 15, 10, 10, 10] 但这种分隔方式的元素总和（76）小于上一种。
\n\n

示例 2：

\n\n
\n输入：arr = [1,4,1,5,7,3,6,1,9,9,3], k = 4\n输出：83\n
\n\n

示例 3：

\n\n
\n输入：arr = [1], k = 1\n输出：1\n
\n\n

 

\n\n

提示：

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