{ "data": { "question": { "questionId": "3056", "questionFrontendId": "2849", "categoryTitle": "Algorithms", "boundTopicId": 2435305, "title": "Determine if a Cell Is Reachable at a Given Time", "titleSlug": "determine-if-a-cell-is-reachable-at-a-given-time", "content": "

You are given four integers sx, sy, fx, fy, and a non-negative integer t.

\n\n

In an infinite 2D grid, you start at the cell (sx, sy). Each second, you must move to any of its adjacent cells.

\n\n

Return true if you can reach cell (fx, fy) after exactly t seconds, or false otherwise.

\n\n

A cell's adjacent cells are the 8 cells around it that share at least one corner with it. You can visit the same cell several times.

\n\n

 

\n

Example 1:

\n\"\"\n
\nInput: sx = 2, sy = 4, fx = 7, fy = 7, t = 6\nOutput: true\nExplanation: Starting at cell (2, 4), we can reach cell (7, 7) in exactly 6 seconds by going through the cells depicted in the picture above. \n
\n\n

Example 2:

\n\"\"\n
\nInput: sx = 3, sy = 1, fx = 7, fy = 3, t = 3\nOutput: false\nExplanation: Starting at cell (3, 1), it takes at least 4 seconds to reach cell (7, 3) by going through the cells depicted in the picture above. Hence, we cannot reach cell (7, 3) at the third second.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "判断能否在给定时间到达单元格", "translatedContent": "

给你四个整数 sx、sy、fx、fy  以及一个 非负整数 t 。

\n\n

在一个无限的二维网格中，你从单元格 (sx, sy) 开始出发。每一秒，你 必须 移动到任一与之前所处单元格相邻的单元格中。

\n\n

如果你能在 恰好 t 秒 后到达单元格 (fx, fy) ，返回 true ；否则，返回  false 。

\n\n

单元格的 相邻单元格 是指该单元格周围与其至少共享一个角的 8 个单元格。你可以多次访问同一个单元格。

\n\n

 

\n\n

示例 1：

\n\"\"\n
\n输入：sx = 2, sy = 4, fx = 7, fy = 7, t = 6\n输出：true\n解释：从单元格 (2, 4) 开始出发，穿过上图标注的单元格，可以在恰好 6 秒后到达单元格 (7, 7) 。 \n
\n\n

示例 2：

\n\"\"\n
\n输入：sx = 3, sy = 1, fx = 7, fy = 3, t = 3\n输出：false\n解释：从单元格 (3, 1) 开始出发，穿过上图标注的单元格，至少需要 4 秒后到达单元格 (7, 3) 。 因此，无法在 3 秒后到达单元格 (7, 3) 。\n
\n\n

 

\n\n

提示：

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exact-integer? exact-integer? exact-integer? exact-integer? boolean?)\n\n )", "__typename": "CodeSnippetNode" }, { "lang": "Erlang", "langSlug": "erlang", "code": "-spec is_reachable_at_time(Sx :: integer(), Sy :: integer(), Fx :: integer(), Fy :: integer(), T :: integer()) -> boolean().\nis_reachable_at_time(Sx, Sy, Fx, Fy, T) ->\n .", "__typename": "CodeSnippetNode" }, { "lang": "Elixir", "langSlug": "elixir", "code": "defmodule Solution do\n @spec is_reachable_at_time(sx :: integer, sy :: integer, fx :: integer, fy :: integer, t :: integer) :: boolean\n def is_reachable_at_time(sx, sy, fx, fy, t) do\n\n end\nend", "__typename": "CodeSnippetNode" } ], "stats": "{\"totalAccepted\": \"5.7K\", \"totalSubmission\": \"23.2K\", \"totalAcceptedRaw\": 5691, \"totalSubmissionRaw\": 23174, \"acRate\": \"24.6%\"}", "hints": [ "Minimum time to reach the cell should be less than or equal to given time.", "The answer is true if t is greater or equal than the Chebyshev distance from (sx, sy) to (fx, fy). 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