You are given a 0-indexed array nums that consists of n distinct positive integers. Apply m operations to this array, where in the ith operation you replace the number operations[i][0] with operations[i][1].
It is guaranteed that in the ith operation:
operations[i][0] exists in nums.operations[i][1] does not exist in nums.Return the array obtained after applying all the operations.
\n\n\n
Example 1:
\n\n\nInput: nums = [1,2,4,6], operations = [[1,3],[4,7],[6,1]]\nOutput: [3,2,7,1]\nExplanation: We perform the following operations on nums:\n- Replace the number 1 with 3. nums becomes [3,2,4,6].\n- Replace the number 4 with 7. nums becomes [3,2,7,6].\n- Replace the number 6 with 1. nums becomes [3,2,7,1].\nWe return the final array [3,2,7,1].\n\n\n
Example 2:
\n\n\nInput: nums = [1,2], operations = [[1,3],[2,1],[3,2]]\nOutput: [2,1]\nExplanation: We perform the following operations to nums:\n- Replace the number 1 with 3. nums becomes [3,2].\n- Replace the number 2 with 1. nums becomes [3,1].\n- Replace the number 3 with 2. nums becomes [2,1].\nWe return the array [2,1].\n\n\n
\n
Constraints:
\n\nn == nums.lengthm == operations.length1 <= n, m <= 105nums are distinct.operations[i].length == 21 <= nums[i], operations[i][0], operations[i][1] <= 106operations[i][0] will exist in nums when applying the ith operation.operations[i][1] will not exist in nums when applying the ith operation.Compiled with clang 11 using the latest C++ 17 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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