You are given a 0-indexed integer array nums of even length.
As long as nums is not empty, you must repetitively:
nums and remove it.nums and remove it.The average of two numbers a and b is (a + b) / 2.
2 and 3 is (2 + 3) / 2 = 2.5.Return the number of distinct averages calculated using the above process.
\n\nNote that when there is a tie for a minimum or maximum number, any can be removed.
\n\n\n
Example 1:
\n\n\nInput: nums = [4,1,4,0,3,5]\nOutput: 2\nExplanation:\n1. Remove 0 and 5, and the average is (0 + 5) / 2 = 2.5. Now, nums = [4,1,4,3].\n2. Remove 1 and 4. The average is (1 + 4) / 2 = 2.5, and nums = [4,3].\n3. Remove 3 and 4, and the average is (3 + 4) / 2 = 3.5.\nSince there are 2 distinct numbers among 2.5, 2.5, and 3.5, we return 2.\n\n\n
Example 2:
\n\n\nInput: nums = [1,100]\nOutput: 1\nExplanation:\nThere is only one average to be calculated after removing 1 and 100, so we return 1.\n\n\n
\n
Constraints:
\n\n2 <= nums.length <= 100nums.length is even.0 <= nums[i] <= 100Compiled with clang 11 using the latest C++ 17 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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