{ "data": { "question": { "questionId": "2726", "questionFrontendId": "2612", "boundTopicId": null, "title": "Minimum Reverse Operations", "titleSlug": "minimum-reverse-operations", "content": "
You are given an integer n
and an integer p
in the range [0, n - 1]
. Representing a 0-indexed array arr
of length n
where all positions are set to 0
's, except position p
which is set to 1
.
You are also given an integer array banned
containing some positions from the array. For the ith position in banned
, arr[banned[i]] = 0
, and banned[i] != p
.
You can perform multiple operations on arr
. In an operation, you can choose a subarray with size k
and reverse the subarray. However, the 1
in arr
should never go to any of the positions in banned
. In other words, after each operation arr[banned[i]]
remains 0
.
Return an array ans
where for each i
from [0, n - 1]
, ans[i]
is the minimum number of reverse operations needed to bring the 1
to position i
in arr, or -1
if it is impossible.
ans[i]
are independent for all i
's.\n
Example 1:
\n\n\nInput: n = 4, p = 0, banned = [1,2], k = 4\nOutput: [0,-1,-1,1]\nExplanation: In this case\n\nk = 4
so there is only one possible reverse operation we can perform, which is reversing the whole array. Initially, 1 is placed at position 0 so the amount of operations we need for position 0 is0
. We can never place a 1 on the banned positions, so the answer for positions 1 and 2 is-1
. Finally, with one reverse operation we can bring the 1 to index 3, so the answer for position 3 is1
. \n
Example 2:
\n\n\nInput: n = 5, p = 0, banned = [2,4], k = 3\nOutput: [0,-1,-1,-1,-1]\nExplanation: In this case the 1 is initially at position 0, so the answer for that position is\n\n0
. We can perform reverse operations of size 3. The 1 is currently located at position 0, so we need to reverse the subarray[0, 2]
for it to leave that position, but reversing that subarray makes position 2 have a 1, which shouldn't happen. So, we can't move the 1 from position 0, making the result for all the other positions-1
. \n
Example 3:
\n\n\nInput: n = 4, p = 2, banned = [0,1,3], k = 1\nOutput: [-1,-1,0,-1]\nExplanation: In this case we can only perform reverse operations of size 1. So the 1 never changes its position.\n\n\n
\n
Constraints:
\n\n1 <= n <= 105
0 <= p <= n - 1
0 <= banned.length <= n - 1
0 <= banned[i] <= n - 1
1 <= k <= n
banned[i] != p
banned
are unique Compiled with clang 11
using the latest C++ 17 standard.
Your code is compiled with level two optimization (-O2
). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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Python 2.7.12
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\\r\\n\\r\\nFor Map/TreeMap data structure, you may use sortedcontainers library.
\\r\\n\\r\\nNote that Python 2.7 will not be maintained past 2020. For the latest Python, please choose Python3 instead.
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Node.js 16.13.2
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Your code is run with --harmony
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lodash.js library is included by default.
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Some common data structure implementations are provided in the Algorithms module: https://www.rubydoc.info/github/kanwei/algorithms/Algorithms
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Go 1.17.6
.
Support https://godoc.org/github.com/emirpasic/gods library.
\"], \"python3\": [\"Python3\", \"Python 3.10
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Most libraries are already imported automatically for your convenience, such as array, bisect, collections. If you need more libraries, you can import it yourself.
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Kotlin 1.3.10
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Rust 1.58.1
Supports rand v0.6\\u00a0from crates.io
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With bcmath module
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Dart 2.17.3
\\r\\n\\r\\nYour code will be run directly without compiling
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