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            "title": "Check if Number Has Equal Digit Count and Digit Value",
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            "content": "<p>You are given a <strong>0-indexed</strong> string <code>num</code> of length <code>n</code> consisting of digits.</p>\n\n<p>Return <code>true</code> <em>if for <strong>every</strong> index </em><code>i</code><em> in the range </em><code>0 &lt;= i &lt; n</code><em>, the digit </em><code>i</code><em> occurs </em><code>num[i]</code><em> times in </em><code>num</code><em>, otherwise return </em><code>false</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> num = &quot;1210&quot;\n<strong>Output:</strong> true\n<strong>Explanation:</strong>\nnum[0] = &#39;1&#39;. The digit 0 occurs once in num.\nnum[1] = &#39;2&#39;. The digit 1 occurs twice in num.\nnum[2] = &#39;1&#39;. The digit 2 occurs once in num.\nnum[3] = &#39;0&#39;. The digit 3 occurs zero times in num.\nThe condition holds true for every index in &quot;1210&quot;, so return true.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> num = &quot;030&quot;\n<strong>Output:</strong> false\n<strong>Explanation:</strong>\nnum[0] = &#39;0&#39;. The digit 0 should occur zero times, but actually occurs twice in num.\nnum[1] = &#39;3&#39;. The digit 1 should occur three times, but actually occurs zero times in num.\nnum[2] = &#39;0&#39;. The digit 2 occurs zero times in num.\nThe indices 0 and 1 both violate the condition, so return false.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == num.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 10</code></li>\n\t<li><code>num</code> consists of digits.</li>\n</ul>\n",
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                    "code": "class Solution(object):\n    def digitCount(self, num):\n        \"\"\"\n        :type num: str\n        :rtype: bool\n        \"\"\"\n        ",
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