You are given an integer array nums and an integer k. You may partition nums into one or more subsequences such that each element in nums appears in exactly one of the subsequences.
Return the minimum number of subsequences needed such that the difference between the maximum and minimum values in each subsequence is at most k.
A subsequence is a sequence that can be derived from another sequence by deleting some or no elements without changing the order of the remaining elements.
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Example 1:
\n\n\nInput: nums = [3,6,1,2,5], k = 2\nOutput: 2\nExplanation:\nWe can partition nums into the two subsequences [3,1,2] and [6,5].\nThe difference between the maximum and minimum value in the first subsequence is 3 - 1 = 2.\nThe difference between the maximum and minimum value in the second subsequence is 6 - 5 = 1.\nSince two subsequences were created, we return 2. It can be shown that 2 is the minimum number of subsequences needed.\n\n\n
Example 2:
\n\n\nInput: nums = [1,2,3], k = 1\nOutput: 2\nExplanation:\nWe can partition nums into the two subsequences [1,2] and [3].\nThe difference between the maximum and minimum value in the first subsequence is 2 - 1 = 1.\nThe difference between the maximum and minimum value in the second subsequence is 3 - 3 = 0.\nSince two subsequences were created, we return 2. Note that another optimal solution is to partition nums into the two subsequences [1] and [2,3].\n\n\n
Example 3:
\n\n\nInput: nums = [2,2,4,5], k = 0\nOutput: 3\nExplanation:\nWe can partition nums into the three subsequences [2,2], [4], and [5].\nThe difference between the maximum and minimum value in the first subsequences is 2 - 2 = 0.\nThe difference between the maximum and minimum value in the second subsequences is 4 - 4 = 0.\nThe difference between the maximum and minimum value in the third subsequences is 5 - 5 = 0.\nSince three subsequences were created, we return 3. It can be shown that 3 is the minimum number of subsequences needed.\n\n\n
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Constraints:
\n\n1 <= nums.length <= 1050 <= nums[i] <= 1050 <= k <= 105给你一个整数数组 nums 和一个整数 k 。你可以将 nums 划分成一个或多个 子序列 ，使 nums 中的每个元素都 恰好 出现在一个子序列中。
在满足每个子序列中最大值和最小值之间的差值最多为 k 的前提下，返回需要划分的 最少 子序列数目。
子序列 本质是一个序列，可以通过删除另一个序列中的某些元素（或者不删除）但不改变剩下元素的顺序得到。
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示例 1：
\n\n\n输入：nums = [3,6,1,2,5], k = 2\n输出：2\n解释：\n可以将 nums 划分为两个子序列 [3,1,2] 和 [6,5] 。\n第一个子序列中最大值和最小值的差值是 3 - 1 = 2 。\n第二个子序列中最大值和最小值的差值是 6 - 5 = 1 。\n由于创建了两个子序列，返回 2 。可以证明需要划分的最少子序列数目就是 2 。\n\n\n
示例 2：
\n\n\n输入：nums = [1,2,3], k = 1\n输出：2\n解释：\n可以将 nums 划分为两个子序列 [1,2] 和 [3] 。\n第一个子序列中最大值和最小值的差值是 2 - 1 = 1 。\n第二个子序列中最大值和最小值的差值是 3 - 3 = 0 。\n由于创建了两个子序列，返回 2 。注意，另一种最优解法是将 nums 划分成子序列 [1] 和 [2,3] 。\n\n\n
示例 3：
\n\n\n输入：nums = [2,2,4,5], k = 0\n输出：3\n解释：\n可以将 nums 划分为三个子序列 [2,2]、[4] 和 [5] 。\n第一个子序列中最大值和最小值的差值是 2 - 2 = 0 。\n第二个子序列中最大值和最小值的差值是 4 - 4 = 0 。\n第三个子序列中最大值和最小值的差值是 5 - 5 = 0 。\n由于创建了三个子序列，返回 3 。可以证明需要划分的最少子序列数目就是 3 。\n\n\n
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提示：
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