{ "data": { "question": { "questionId": "1699", "questionFrontendId": "1577", "boundTopicId": null, "title": "Number of Ways Where Square of Number Is Equal to Product of Two Numbers", "titleSlug": "number-of-ways-where-square-of-number-is-equal-to-product-of-two-numbers", "content": "

Given two arrays of integers nums1 and nums2, return the number of triplets formed (type 1 and type 2) under the following rules:

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Example 1:

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\nInput: nums1 = [7,4], nums2 = [5,2,8,9]\nOutput: 1\nExplanation: Type 1: (1, 1, 2), nums1[1]2 = nums2[1] * nums2[2]. (42 = 2 * 8). \n
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Example 2:

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\nInput: nums1 = [1,1], nums2 = [1,1,1]\nOutput: 9\nExplanation: All Triplets are valid, because 12 = 1 * 1.\nType 1: (0,0,1), (0,0,2), (0,1,2), (1,0,1), (1,0,2), (1,1,2).  nums1[i]2 = nums2[j] * nums2[k].\nType 2: (0,0,1), (1,0,1), (2,0,1). nums2[i]2 = nums1[j] * nums1[k].\n
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Example 3:

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\nInput: nums1 = [7,7,8,3], nums2 = [1,2,9,7]\nOutput: 2\nExplanation: There are 2 valid triplets.\nType 1: (3,0,2).  nums1[3]2 = nums2[0] * nums2[2].\nType 2: (3,0,1).  nums2[3]2 = nums1[0] * nums1[1].\n
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Constraints:

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Python 2.7.12.

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