You are given two strings s and t such that every character occurs at most once in s and t is a permutation of s.
The permutation difference between s and t is defined as the sum of the absolute difference between the index of the occurrence of each character in s and the index of the occurrence of the same character in t.
Return the permutation difference between s and t.
\n
Example 1:
\n\nInput: s = "abc", t = "bac"
\n\nOutput: 2
\n\nExplanation:
\n\nFor s = "abc" and t = "bac", the permutation difference of s and t is equal to the sum of:
"a" in s and the index of the occurrence of "a" in t."b" in s and the index of the occurrence of "b" in t."c" in s and the index of the occurrence of "c" in t.That is, the permutation difference between s and t is equal to |0 - 1| + |2 - 2| + |1 - 0| = 2.
Example 2:
\n\nInput: s = "abcde", t = "edbac"
\n\nOutput: 12
\n\nExplanation: The permutation difference between s and t is equal to |0 - 3| + |1 - 2| + |2 - 4| + |3 - 1| + |4 - 0| = 12.
\n
Constraints:
\n\n1 <= s.length <= 26s.t is a permutation of s.s consists only of lowercase English letters.给你两个字符串 s 和 t，每个字符串中的字符都不重复，且 t 是 s 的一个排列。
排列差 定义为 s 和 t 中每个字符在两个字符串中位置的绝对差值之和。
返回 s 和 t 之间的 排列差 。
\n\n
示例 1：
\n\n输入：s = \"abc\", t = \"bac\"
\n\n输出：2
\n\n解释：
\n\n对于 s = \"abc\" 和 t = \"bac\"，排列差是：
\"a\" 在 s 中的位置与在 t 中的位置之差的绝对值。\"b\" 在 s 中的位置与在 t 中的位置之差的绝对值。\"c\" 在 s 中的位置与在 t 中的位置之差的绝对值。即，s 和 t 的排列差等于 |0 - 1| + |2 - 2| + |1 - 0| = 2。
示例 2：
\n\n输入：s = \"abcde\", t = \"edbac\"
\n\n输出：12
\n\n解释： s 和 t 的排列差等于 |0 - 3| + |1 - 2| + |2 - 4| + |3 - 1| + |4 - 0| = 12。
\n\n
提示：
\n\n1 <= s.length <= 26s 中最多出现一次。t 是 s 的一个排列。s 仅由小写英文字母组成。s then in string t."
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