{ "data": { "question": { "questionId": "3525", "questionFrontendId": "3259", "categoryTitle": "Algorithms", "boundTopicId": 2883077, "title": "Maximum Energy Boost From Two Drinks", "titleSlug": "maximum-energy-boost-from-two-drinks", "content": "

You are given two integer arrays energyDrinkA and energyDrinkB of the same length n by a futuristic sports scientist. These arrays represent the energy boosts per hour provided by two different energy drinks, A and B, respectively.

\n\n

You want to maximize your total energy boost by drinking one energy drink per hour. However, if you want to switch from consuming one energy drink to the other, you need to wait for one hour to cleanse your system (meaning you won't get any energy boost in that hour).

\n\n

Return the maximum total energy boost you can gain in the next n hours.

\n\n

Note that you can start consuming either of the two energy drinks.

\n\n

 

\n

Example 1:

\n\n
\n

Input: energyDrinkA = [1,3,1], energyDrinkB = [3,1,1]

\n\n

Output: 5

\n\n

Explanation:

\n\n

To gain an energy boost of 5, drink only the energy drink A (or only B).

\n
\n\n

Example 2:

\n\n
\n

Input: energyDrinkA = [4,1,1], energyDrinkB = [1,1,3]

\n\n

Output: 7

\n\n

Explanation:

\n\n

To gain an energy boost of 7:

\n\n\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "超级饮料的最大强化能量", "translatedContent": "

来自未来的体育科学家给你两个整数数组 energyDrinkAenergyDrinkB,数组长度都等于 n。这两个数组分别代表 A、B 两种不同能量饮料每小时所能提供的强化能量。

\n\n

你需要每小时饮用一种能量饮料来 最大化 你的总强化能量。然而,如果从一种能量饮料切换到另一种,你需要等待一小时来梳理身体的能量体系(在那个小时里你将不会获得任何强化能量)。

\n\n

返回在接下来的 n 小时内你能获得的 最大 总强化能量。

\n\n

注意 你可以选择从饮用任意一种能量饮料开始。

\n\n

 

\n\n

示例 1:

\n\n
\n

输入:energyDrinkA = [1,3,1], energyDrinkB = [3,1,1]

\n\n

输出:5

\n\n

解释:

\n\n

要想获得 5 点强化能量,需要选择只饮用能量饮料 A(或者只饮用 B)。

\n
\n\n

示例 2:

\n\n
\n

输入:energyDrinkA = [4,1,1], energyDrinkB = [1,1,3]

\n\n

输出:7

\n\n

解释:

\n\n\n
\n\n

 

\n\n

提示:

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(listof exact-integer?) exact-integer?)\n )", "__typename": "CodeSnippetNode" }, { "lang": "Erlang", "langSlug": "erlang", "code": "-spec max_energy_boost(EnergyDrinkA :: [integer()], EnergyDrinkB :: [integer()]) -> integer().\nmax_energy_boost(EnergyDrinkA, EnergyDrinkB) ->\n .", "__typename": "CodeSnippetNode" }, { "lang": "Elixir", "langSlug": "elixir", "code": "defmodule Solution do\n @spec max_energy_boost(energy_drink_a :: [integer], energy_drink_b :: [integer]) :: integer\n def max_energy_boost(energy_drink_a, energy_drink_b) do\n \n end\nend", "__typename": "CodeSnippetNode" } ], "stats": "{\"totalAccepted\": \"3.8K\", \"totalSubmission\": \"6.8K\", \"totalAcceptedRaw\": 3785, \"totalSubmissionRaw\": 6757, \"acRate\": \"56.0%\"}", "hints": [ "Can we solve it using dynamic programming?", "Define dpA[i] as the maximum energy boost if we consider only the first i + 1 hours such that in the last hour, we drink the energy drink A.", "Similarly define dpB[i].", "dpA[i] = max(dpA[i - 1], dpB[i - 2]) + energyDrinkA[i]", "Similarly, fill dpB.", "The answer is max(dpA[n - 1], dpB[n - 1])." ], "solution": null, "status": null, "sampleTestCase": "[1,3,1]\n[3,1,1]", "metaData": "{\n \"name\": \"maxEnergyBoost\",\n \"params\": [\n {\n \"name\": \"energyDrinkA\",\n \"type\": \"integer[]\"\n },\n {\n \"type\": \"integer[]\",\n \"name\": \"energyDrinkB\"\n }\n ],\n \"return\": {\n \"type\": \"long\"\n }\n}", "judgerAvailable": true, "judgeType": "large", "mysqlSchemas": [], "enableRunCode": true, "envInfo": "{\"cpp\":[\"C++\",\"

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