{ "data": { "question": { "questionId": "1482", "questionFrontendId": "1365", "categoryTitle": "Algorithms", "boundTopicId": 112311, "title": "How Many Numbers Are Smaller Than the Current Number", "titleSlug": "how-many-numbers-are-smaller-than-the-current-number", "content": "
Given the array nums
, for each nums[i]
find out how many numbers in the array are smaller than it. That is, for each nums[i]
you have to count the number of valid j's
such that j != i
and nums[j] < nums[i]
.
Return the answer in an array.
\n\n\n
Example 1:
\n\n\nInput: nums = [8,1,2,2,3]\nOutput: [4,0,1,1,3]\nExplanation: \nFor nums[0]=8 there exist four smaller numbers than it (1, 2, 2 and 3). \nFor nums[1]=1 does not exist any smaller number than it.\nFor nums[2]=2 there exist one smaller number than it (1). \nFor nums[3]=2 there exist one smaller number than it (1). \nFor nums[4]=3 there exist three smaller numbers than it (1, 2 and 2).\n\n\n
Example 2:
\n\n\nInput: nums = [6,5,4,8]\nOutput: [2,1,0,3]\n\n\n
Example 3:
\n\n\nInput: nums = [7,7,7,7]\nOutput: [0,0,0,0]\n\n\n
\n
Constraints:
\n\n2 <= nums.length <= 500
0 <= nums[i] <= 100
给你一个数组 nums
,对于其中每个元素 nums[i]
,请你统计数组中比它小的所有数字的数目。
换而言之,对于每个 nums[i]
你必须计算出有效的 j
的数量,其中 j
满足 j != i
且 nums[j] < nums[i]
。
以数组形式返回答案。
\n\n\n\n
示例 1:
\n\n输入:nums = [8,1,2,2,3]\n输出:[4,0,1,1,3]\n解释: \n对于 nums[0]=8 存在四个比它小的数字:(1,2,2 和 3)。 \n对于 nums[1]=1 不存在比它小的数字。\n对于 nums[2]=2 存在一个比它小的数字:(1)。 \n对于 nums[3]=2 存在一个比它小的数字:(1)。 \n对于 nums[4]=3 存在三个比它小的数字:(1,2 和 2)。\n\n\n
示例 2:
\n\n输入:nums = [6,5,4,8]\n输出:[2,1,0,3]\n\n\n
示例 3:
\n\n输入:nums = [7,7,7,7]\n输出:[0,0,0,0]\n\n\n
\n\n
提示:
\n\n2 <= nums.length <= 500
0 <= nums[i] <= 100
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