You are given an integer array nums. The uniqueness array of nums is the sorted array that contains the number of distinct elements of all the subarrays of nums. In other words, it is a sorted array consisting of distinct(nums[i..j]), for all 0 <= i <= j < nums.length.
Here, distinct(nums[i..j]) denotes the number of distinct elements in the subarray that starts at index i and ends at index j.
Return the median of the uniqueness array of nums.
Note that the median of an array is defined as the middle element of the array when it is sorted in non-decreasing order. If there are two choices for a median, the smaller of the two values is taken.
\n\n\n
Example 1:
\n\nInput: nums = [1,2,3]
\n\nOutput: 1
\n\nExplanation:
\n\nThe uniqueness array of nums is [distinct(nums[0..0]), distinct(nums[1..1]), distinct(nums[2..2]), distinct(nums[0..1]), distinct(nums[1..2]), distinct(nums[0..2])] which is equal to [1, 1, 1, 2, 2, 3]. The uniqueness array has a median of 1. Therefore, the answer is 1.
Example 2:
\n\nInput: nums = [3,4,3,4,5]
\n\nOutput: 2
\n\nExplanation:
\n\nThe uniqueness array of nums is [1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3]. The uniqueness array has a median of 2. Therefore, the answer is 2.
Example 3:
\n\nInput: nums = [4,3,5,4]
\n\nOutput: 2
\n\nExplanation:
\n\nThe uniqueness array of nums is [1, 1, 1, 1, 2, 2, 2, 3, 3, 3]. The uniqueness array has a median of 2. Therefore, the answer is 2.
\n
Constraints:
\n\n1 <= nums.length <= 1051 <= nums[i] <= 105给你一个整数数组 nums 。数组 nums 的 唯一性数组 是一个按元素从小到大排序的数组，包含了 nums 的所有非空子数组中不同元素的个数。
换句话说，这是由所有 0 <= i <= j < nums.length 的 distinct(nums[i..j]) 组成的递增数组。
其中，distinct(nums[i..j]) 表示从下标 i 到下标 j 的子数组中不同元素的数量。
返回 nums 唯一性数组 的 中位数 。
注意，数组的 中位数 定义为有序数组的中间元素。如果有两个中间元素，则取值较小的那个。
\n\n\n\n
示例 1：
\n\n输入：nums = [1,2,3]
\n\n输出：1
\n\n解释：
\n\nnums 的唯一性数组为 [distinct(nums[0..0]), distinct(nums[1..1]), distinct(nums[2..2]), distinct(nums[0..1]), distinct(nums[1..2]), distinct(nums[0..2])]，即 [1, 1, 1, 2, 2, 3] 。唯一性数组的中位数为 1 ，因此答案是 1 。
示例 2：
\n\n输入：nums = [3,4,3,4,5]
\n\n输出：2
\n\n解释：
\n\nnums 的唯一性数组为 [1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3] 。唯一性数组的中位数为 2 ，因此答案是 2 。
示例 3：
\n\n输入：nums = [4,3,5,4]
\n\n输出：2
\n\n解释：
\n\nnums 的唯一性数组为 [1, 1, 1, 1, 2, 2, 2, 3, 3, 3] 。唯一性数组的中位数为 2 ，因此答案是 2 。
\n\n
提示：
\n\n1 <= nums.length <= 1051 <= nums[i] <= 105x, you need to check if x is the median, to the left of the median, or to the right of the media. You can do that by counting the number of sub-arrays nums[i…j] such that distinct(num[i…j]) <= x.",
"Use the sliding window to solve the counting problem in the hint above."
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