You are given a 0-indexed array nums consisting of positive integers.
You can do the following operation on the array any number of times:
\n\ni such that 0 <= i < nums.length - 1 and nums[i] <= nums[i + 1]. Replace the element nums[i + 1] with nums[i] + nums[i + 1] and delete the element nums[i] from the array.Return the value of the largest element that you can possibly obtain in the final array.
\n\n\n
Example 1:
\n\n\nInput: nums = [2,3,7,9,3]\nOutput: 21\nExplanation: We can apply the following operations on the array:\n- Choose i = 0. The resulting array will be nums = [5,7,9,3].\n- Choose i = 1. The resulting array will be nums = [5,16,3].\n- Choose i = 0. The resulting array will be nums = [21,3].\nThe largest element in the final array is 21. It can be shown that we cannot obtain a larger element.\n\n\n
Example 2:
\n\n\nInput: nums = [5,3,3]\nOutput: 11\nExplanation: We can do the following operations on the array:\n- Choose i = 1. The resulting array will be nums = [5,6].\n- Choose i = 0. The resulting array will be nums = [11].\nThere is only one element in the final array, which is 11.\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 1051 <= nums[i] <= 106Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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