{ "data": { "question": { "questionId": "3243", "questionFrontendId": "2999", "boundTopicId": null, "title": "Count the Number of Powerful Integers", "titleSlug": "count-the-number-of-powerful-integers", "content": "
You are given three integers start
, finish
, and limit
. You are also given a 0-indexed string s
representing a positive integer.
A positive integer x
is called powerful if it ends with s
(in other words, s
is a suffix of x
) and each digit in x
is at most limit
.
Return the total number of powerful integers in the range [start..finish]
.
A string x
is a suffix of a string y
if and only if x
is a substring of y
that starts from some index (including 0
) in y
and extends to the index y.length - 1
. For example, 25
is a suffix of 5125
whereas 512
is not.
\n
Example 1:
\n\n\nInput: start = 1, finish = 6000, limit = 4, s = "124"\nOutput: 5\nExplanation: The powerful integers in the range [1..6000] are 124, 1124, 2124, 3124, and, 4124. All these integers have each digit <= 4, and "124" as a suffix. Note that 5124 is not a powerful integer because the first digit is 5 which is greater than 4.\nIt can be shown that there are only 5 powerful integers in this range.\n\n\n
Example 2:
\n\n\nInput: start = 15, finish = 215, limit = 6, s = "10"\nOutput: 2\nExplanation: The powerful integers in the range [15..215] are 110 and 210. All these integers have each digit <= 6, and "10" as a suffix.\nIt can be shown that there are only 2 powerful integers in this range.\n\n\n
Example 3:
\n\n\nInput: start = 1000, finish = 2000, limit = 4, s = "3000"\nOutput: 0\nExplanation: All integers in the range [1000..2000] are smaller than 3000, hence "3000" cannot be a suffix of any integer in this range.\n\n\n
\n
Constraints:
\n\n1 <= start <= finish <= 1015
1 <= limit <= 9
1 <= s.length <= floor(log10(finish)) + 1
s
only consists of numeric digits which are at most limit
.s
does not have leading zeros.[1, x]
.",
"Let dp[i][j]
be the number of integers that have i
digits (with allowed leading 0s) and j
refers to the comparison between the current number and the prefix of x
, j == 0
if the i-digit number formed currently is identical to the leftmost i
digits of x
, else if j ==1
it means the i-digit number is smaller than the leftmost i
digits of x
.",
"The answer is count[finish] - count[start - 1]
, where count[i]
refers to the number of powerful integers in the range [1..i]
."
],
"solution": null,
"status": null,
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