A parentheses string is a non-empty string consisting only of '(' and ')'. It is valid if any of the following conditions is true:
().AB (A concatenated with B), where A and B are valid parentheses strings.(A), where A is a valid parentheses string.You are given a parentheses string s and a string locked, both of length n. locked is a binary string consisting only of '0's and '1's. For each index i of locked,
locked[i] is '1', you cannot change s[i].locked[i] is '0', you can change s[i] to either '(' or ')'.Return true if you can make s a valid parentheses string. Otherwise, return false.
\n
Example 1:
\n![\"\"](\"https://assets.leetcode.com/uploads/2021/11/06/eg1.png\")
\n\nInput: s = "))()))", locked = "010100"\nOutput: true\nExplanation: locked[1] == '1' and locked[3] == '1', so we cannot change s[1] or s[3].\nWe change s[0] and s[4] to '(' while leaving s[2] and s[5] unchanged to make s valid.\n\nExample 2:
\n\n\nInput: s = "()()", locked = "0000"\nOutput: true\nExplanation: We do not need to make any changes because s is already valid.\n\n\n
Example 3:
\n\n\nInput: s = ")", locked = "0"\nOutput: false\nExplanation: locked permits us to change s[0]. \nChanging s[0] to either '(' or ')' will not make s valid.\n\n\n\n
Constraints:
\n\nn == s.length == locked.length1 <= n <= 105s[i] is either '(' or ')'.locked[i] is either '0' or '1'.Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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