Initially, you have a bank account balance of 100 dollars.
You are given an integer purchaseAmount representing the amount you will spend on a purchase in dollars.
At the store where you will make the purchase, the purchase amount is rounded to the nearest multiple of 10. In other words, you pay a non-negative amount, roundedAmount, such that roundedAmount is a multiple of 10 and abs(roundedAmount - purchaseAmount) is minimized.
If there is more than one nearest multiple of 10, the largest multiple is chosen.
Return an integer denoting your account balance after making a purchase worth purchaseAmount dollars from the store.
Note: 0 is considered to be a multiple of 10 in this problem.
\n
Example 1:
\n\n\nInput: purchaseAmount = 9\nOutput: 90\nExplanation: In this example, the nearest multiple of 10 to 9 is 10. Hence, your account balance becomes 100 - 10 = 90.\n\n\n
Example 2:
\n\n\nInput: purchaseAmount = 15\nOutput: 80\nExplanation: In this example, there are two nearest multiples of 10 to 15: 10 and 20. So, the larger multiple, 20, is chosen.\nHence, your account balance becomes 100 - 20 = 80.\n\n\n
\n
Constraints:
\n\n0 <= purchaseAmount <= 100Compiled with clang 11 using the latest C++ 20 standard.
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