{ "data": { "question": { "questionId": "167", "questionFrontendId": "167", "boundTopicId": null, "title": "Two Sum II - Input Array Is Sorted", "titleSlug": "two-sum-ii-input-array-is-sorted", "content": "
Given a 1-indexed array of integers numbers
that is already sorted in non-decreasing order, find two numbers such that they add up to a specific target
number. Let these two numbers be numbers[index1]
and numbers[index2]
where 1 <= index1 < index2 <= numbers.length
.
Return the indices of the two numbers, index1
and index2
, added by one as an integer array [index1, index2]
of length 2.
The tests are generated such that there is exactly one solution. You may not use the same element twice.
\n\nYour solution must use only constant extra space.
\n\n\n
Example 1:
\n\n\nInput: numbers = [2,7,11,15], target = 9\nOutput: [1,2]\nExplanation: The sum of 2 and 7 is 9. Therefore, index1 = 1, index2 = 2. We return [1, 2].\n\n\n
Example 2:
\n\n\nInput: numbers = [2,3,4], target = 6\nOutput: [1,3]\nExplanation: The sum of 2 and 4 is 6. Therefore index1 = 1, index2 = 3. We return [1, 3].\n\n\n
Example 3:
\n\n\nInput: numbers = [-1,0], target = -1\nOutput: [1,2]\nExplanation: The sum of -1 and 0 is -1. Therefore index1 = 1, index2 = 2. We return [1, 2].\n\n\n
\n
Constraints:
\n\n2 <= numbers.length <= 3 * 104
-1000 <= numbers[i] <= 1000
numbers
is sorted in non-decreasing order.-1000 <= target <= 1000
Compiled with clang 11
using the latest C++ 17 standard.
Your code is compiled with level two optimization (-O2
). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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Your code is compiled with debug flag enabled (/debug
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Node.js 16.13.2
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Go 1.17.6
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