{ "data": { "question": { "questionId": "2386", "questionFrontendId": "2293", "boundTopicId": null, "title": "Min Max Game", "titleSlug": "min-max-game", "content": "

You are given a 0-indexed integer array nums whose length is a power of 2.

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Apply the following algorithm on nums:

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    \n\t
  1. Let n be the length of nums. If n == 1, end the process. Otherwise, create a new 0-indexed integer array newNums of length n / 2.
    2. \n\t
  2. For every even index i where 0 <= i < n / 2, assign the value of newNums[i] as min(nums[2 * i], nums[2 * i + 1]).
    3. \n\t
  3. For every odd index i where 0 <= i < n / 2, assign the value of newNums[i] as max(nums[2 * i], nums[2 * i + 1]).
    4. \n\t
  4. Replace the array nums with newNums.
    5. \n\t
  5. Repeat the entire process starting from step 1.
    6. \n
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Return the last number that remains in nums after applying the algorithm.

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Example 1:

\n\"\"\n
\nInput: nums = [1,3,5,2,4,8,2,2]\nOutput: 1\nExplanation: The following arrays are the results of applying the algorithm repeatedly.\nFirst: nums = [1,5,4,2]\nSecond: nums = [1,4]\nThird: nums = [1]\n1 is the last remaining number, so we return 1.\n
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Example 2:

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\nInput: nums = [3]\nOutput: 3\nExplanation: 3 is already the last remaining number, so we return 3.\n
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Constraints:

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Most standard library headers are already included automatically for your convenience.

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Python 2.7.12.

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C# 10 with .NET 6 runtime

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Python 3.10.

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