{ "data": { "question": { "questionId": "1945", "questionFrontendId": "1817", "boundTopicId": null, "title": "Finding the Users Active Minutes", "titleSlug": "finding-the-users-active-minutes", "content": "

You are given the logs for users' actions on LeetCode, and an integer k. The logs are represented by a 2D integer array logs where each logs[i] = [IDi, timei] indicates that the user with IDi performed an action at the minute timei.

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Multiple users can perform actions simultaneously, and a single user can perform multiple actions in the same minute.

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The user active minutes (UAM) for a given user is defined as the number of unique minutes in which the user performed an action on LeetCode. A minute can only be counted once, even if multiple actions occur during it.

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You are to calculate a 1-indexed array answer of size k such that, for each j (1 <= j <= k), answer[j] is the number of users whose UAM equals j.

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Return the array answer as described above.

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Example 1:

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\nInput: logs = [[0,5],[1,2],[0,2],[0,5],[1,3]], k = 5\nOutput: [0,2,0,0,0]\nExplanation:\nThe user with ID=0 performed actions at minutes 5, 2, and 5 again. Hence, they have a UAM of 2 (minute 5 is only counted once).\nThe user with ID=1 performed actions at minutes 2 and 3. Hence, they have a UAM of 2.\nSince both users have a UAM of 2, answer[2] is 2, and the remaining answer[j] values are 0.\n
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Example 2:

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\nInput: logs = [[1,1],[2,2],[2,3]], k = 4\nOutput: [1,1,0,0]\nExplanation:\nThe user with ID=1 performed a single action at minute 1. Hence, they have a UAM of 1.\nThe user with ID=2 performed actions at minutes 2 and 3. Hence, they have a UAM of 2.\nThere is one user with a UAM of 1 and one with a UAM of 2.\nHence, answer[1] = 1, answer[2] = 1, and the remaining values are 0.\n
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Constraints:

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