{ "data": { "question": { "questionId": "881", "questionFrontendId": "851", "categoryTitle": "Algorithms", "boundTopicId": 1518, "title": "Loud and Rich", "titleSlug": "loud-and-rich", "content": "
There is a group of n people labeled from 0 to n - 1 where each person has a different amount of money and a different level of quietness.
You are given an array richer where richer[i] = [ai, bi] indicates that ai has more money than bi and an integer array quiet where quiet[i] is the quietness of the ith person. All the given data in richer are logically correct (i.e., the data will not lead you to a situation where x is richer than y and y is richer than x at the same time).
Return an integer array answer where answer[x] = y if y is the least quiet person (that is, the person y with the smallest value of quiet[y]) among all people who definitely have equal to or more money than the person x.
\n
Example 1:
\n\n\nInput: richer = [[1,0],[2,1],[3,1],[3,7],[4,3],[5,3],[6,3]], quiet = [3,2,5,4,6,1,7,0]\nOutput: [5,5,2,5,4,5,6,7]\nExplanation: \nanswer[0] = 5.\nPerson 5 has more money than 3, which has more money than 1, which has more money than 0.\nThe only person who is quieter (has lower quiet[x]) is person 7, but it is not clear if they have more money than person 0.\nanswer[7] = 7.\nAmong all people that definitely have equal to or more money than person 7 (which could be persons 3, 4, 5, 6, or 7), the person who is the quietest (has lower quiet[x]) is person 7.\nThe other answers can be filled out with similar reasoning.\n\n\n
Example 2:
\n\n\nInput: richer = [], quiet = [0]\nOutput: [0]\n\n\n
\n
Constraints:
\n\nn == quiet.length1 <= n <= 5000 <= quiet[i] < nquiet are unique.0 <= richer.length <= n * (n - 1) / 20 <= ai, bi < nai != biricher are unique.richer are all logically consistent.有一组 n 个人作为实验对象,从 0 到 n - 1 编号,其中每个人都有不同数目的钱,以及不同程度的安静值(quietness)。为了方便起见,我们将编号为 x 的人简称为 \"person x \"。
给你一个数组 richer ,其中 richer[i] = [ai, bi] 表示 person ai 比 person bi 更有钱。另给你一个整数数组 quiet ,其中 quiet[i] 是 person i 的安静值。richer 中所给出的数据 逻辑自洽(也就是说,在 person x 比 person y 更有钱的同时,不会出现 person y 比 person x 更有钱的情况 )。
现在,返回一个整数数组 answer 作为答案,其中 answer[x] = y 的前提是,在所有拥有的钱肯定不少于 person x 的人中,person y 是最安静的人(也就是安静值 quiet[y] 最小的人)。
\n\n
示例 1:
\n\n\n输入:richer = [[1,0],[2,1],[3,1],[3,7],[4,3],[5,3],[6,3]], quiet = [3,2,5,4,6,1,7,0]\n输出:[5,5,2,5,4,5,6,7]\n解释: \nanswer[0] = 5,\nperson 5 比 person 3 有更多的钱,person 3 比 person 1 有更多的钱,person 1 比 person 0 有更多的钱。\n唯一较为安静(有较低的安静值 quiet[x])的人是 person 7,\n但是目前还不清楚他是否比 person 0 更有钱。\nanswer[7] = 7,\n在所有拥有的钱肯定不少于 person 7 的人中(这可能包括 person 3,4,5,6 以及 7),\n最安静(有较低安静值 quiet[x])的人是 person 7。\n其他的答案也可以用类似的推理来解释。\n\n\n
示例 2:
\n\n\n输入:richer = [], quiet = [0]\n输出:[0]\n\n \n\n
提示:
\n\nn == quiet.length1 <= n <= 5000 <= quiet[i] < nquiet 的所有值 互不相同0 <= richer.length <= n * (n - 1) / 20 <= ai, bi < nai != biricher 中的所有数对 互不相同richer 的观察在逻辑上是一致的\\u7248\\u672c\\uff1a \\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528 \\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\"],\"java\":[\"Java\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u88ab\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u5305\\u542b Pair \\u7c7b: https:\\/\\/docs.oracle.com\\/javase\\/8\\/javafx\\/api\\/javafx\\/util\\/Pair.html <\\/p>\"],\"python\":[\"Python\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982\\uff1aarray<\\/a>, 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