<p>You are given a <strong>0-indexed</strong> string <code>s</code> that has lowercase English letters in its <strong>even</strong> indices and digits in its <strong>odd</strong> indices.</p> <p>There is a function <code>shift(c, x)</code>, where <code>c</code> is a character and <code>x</code> is a digit, that returns the <code>x<sup>th</sup></code> character after <code>c</code>.</p> <ul> <li>For example, <code>shift('a', 5) = 'f'</code> and <code>shift('x', 0) = 'x'</code>.</li> </ul> <p>For every <strong>odd</strong> index <code>i</code>, you want to replace the digit <code>s[i]</code> with <code>shift(s[i-1], s[i])</code>.</p> <p>Return <code>s</code><em> after replacing all digits. It is <strong>guaranteed</strong> that </em><code>shift(s[i-1], s[i])</code><em> will never exceed </em><code>'z'</code>.</p> <p> </p> <p><strong>Example 1:</strong></p> <pre> <strong>Input:</strong> s = "a1c1e1" <strong>Output:</strong> "abcdef" <strong>Explanation: </strong>The digits are replaced as follows: - s[1] -> shift('a',1) = 'b' - s[3] -> shift('c',1) = 'd' - s[5] -> shift('e',1) = 'f'</pre> <p><strong>Example 2:</strong></p> <pre> <strong>Input:</strong> s = "a1b2c3d4e" <strong>Output:</strong> "abbdcfdhe" <strong>Explanation: </strong>The digits are replaced as follows: - s[1] -> shift('a',1) = 'b' - s[3] -> shift('b',2) = 'd' - s[5] -> shift('c',3) = 'f' - s[7] -> shift('d',4) = 'h'</pre> <p> </p> <p><strong>Constraints:</strong></p> <ul> <li><code>1 <= s.length <= 100</code></li> <li><code>s</code> consists only of lowercase English letters and digits.</li> <li><code>shift(s[i-1], s[i]) <= 'z'</code> for all <strong>odd</strong> indices <code>i</code>.</li> </ul>