<p>Given an array of integers <code>nums</code> sorted in non-decreasing order, find the starting and ending position of a given <code>target</code> value.</p> <p>If <code>target</code> is not found in the array, return <code>[-1, -1]</code>.</p> <p>You must write an algorithm with <code>O(log n)</code> runtime complexity.</p> <p> </p> <p><strong>Example 1:</strong></p> <pre><strong>Input:</strong> nums = [5,7,7,8,8,10], target = 8 <strong>Output:</strong> [3,4] </pre><p><strong>Example 2:</strong></p> <pre><strong>Input:</strong> nums = [5,7,7,8,8,10], target = 6 <strong>Output:</strong> [-1,-1] </pre><p><strong>Example 3:</strong></p> <pre><strong>Input:</strong> nums = [], target = 0 <strong>Output:</strong> [-1,-1] </pre> <p> </p> <p><strong>Constraints:</strong></p> <ul> <li><code>0 <= nums.length <= 10<sup>5</sup></code></li> <li><code>-10<sup>9</sup> <= nums[i] <= 10<sup>9</sup></code></li> <li><code>nums</code> is a non-decreasing array.</li> <li><code>-10<sup>9</sup> <= target <= 10<sup>9</sup></code></li> </ul>