There are n rooms you need to visit, labeled from 0 to n - 1. Each day is labeled, starting from 0. You will go in and visit one room a day.
Initially on day 0, you visit room 0. The order you visit the rooms for the coming days is determined by the following rules and a given 0-indexed array nextVisit of length n:
i,i an odd number of times (including the current visit), on the next day you will visit a room with a lower or equal room number specified by nextVisit[i] where 0 <= nextVisit[i] <= i;i an even number of times (including the current visit), on the next day you will visit room (i + 1) mod n.Return the label of the first day where you have been in all the rooms. It can be shown that such a day exists. Since the answer may be very large, return it modulo 109 + 7.
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Example 1:
\n\n\nInput: nextVisit = [0,0]\nOutput: 2\nExplanation:\n- On day 0, you visit room 0. The total times you have been in room 0 is 1, which is odd.\n On the next day you will visit room nextVisit[0] = 0\n- On day 1, you visit room 0, The total times you have been in room 0 is 2, which is even.\n On the next day you will visit room (0 + 1) mod 2 = 1\n- On day 2, you visit room 1. This is the first day where you have been in all the rooms.\n\n\n
Example 2:
\n\n\nInput: nextVisit = [0,0,2]\nOutput: 6\nExplanation:\nYour room visiting order for each day is: [0,0,1,0,0,1,2,...].\nDay 6 is the first day where you have been in all the rooms.\n\n\n
Example 3:
\n\n\nInput: nextVisit = [0,1,2,0]\nOutput: 6\nExplanation:\nYour room visiting order for each day is: [0,0,1,1,2,2,3,...].\nDay 6 is the first day where you have been in all the rooms.\n\n\n
\n
Constraints:
\n\nn == nextVisit.length2 <= n <= 1050 <= nextVisit[i] <= iCompiled with clang 11 using the latest C++ 17 standard.
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