{ "data": { "question": { "questionId": "419", "questionFrontendId": "419", "boundTopicId": null, "title": "Battleships in a Board", "titleSlug": "battleships-in-a-board", "content": "
Given an m x n
matrix board
where each cell is a battleship 'X'
or empty '.'
, return the number of the battleships on board
.
Battleships can only be placed horizontally or vertically on board
. In other words, they can only be made of the shape 1 x k
(1
row, k
columns) or k x 1
(k
rows, 1
column), where k
can be of any size. At least one horizontal or vertical cell separates between two battleships (i.e., there are no adjacent battleships).
\n
Example 1:
\n\n\nInput: board = [["X",".",".","X"],[".",".",".","X"],[".",".",".","X"]]\nOutput: 2\n\n\n
Example 2:
\n\n\nInput: board = [["."]]\nOutput: 0\n\n\n
\n
Constraints:
\n\nm == board.length
n == board[i].length
1 <= m, n <= 200
board[i][j]
is either '.'
or 'X'
.\n
Follow up: Could you do it in one-pass, using only O(1)
extra memory and without modifying the values board
?
Compiled with clang 11
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Your code is compiled with level two optimization (-O2
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Most standard library headers are already included automatically for your convenience.
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