{ "data": { "question": { "questionId": "3193", "questionFrontendId": "2932", "boundTopicId": null, "title": "Maximum Strong Pair XOR I", "titleSlug": "maximum-strong-pair-xor-i", "content": "
You are given a 0-indexed integer array nums
. A pair of integers x
and y
is called a strong pair if it satisfies the condition:
|x - y| <= min(x, y)
You need to select two integers from nums
such that they form a strong pair and their bitwise XOR
is the maximum among all strong pairs in the array.
Return the maximum XOR
value out of all possible strong pairs in the array nums
.
Note that you can pick the same integer twice to form a pair.
\n\n\n
Example 1:
\n\n\nInput: nums = [1,2,3,4,5]\nOutput: 7\nExplanation: There are 11 strong pairs in the array nums
: (1, 1), (1, 2), (2, 2), (2, 3), (2, 4), (3, 3), (3, 4), (3, 5), (4, 4), (4, 5) and (5, 5).\nThe maximum XOR possible from these pairs is 3 XOR 4 = 7.\n
\n\nExample 2:
\n\n\nInput: nums = [10,100]\nOutput: 0\nExplanation: There are 2 strong pairs in the array nums
: (10, 10) and (100, 100).\nThe maximum XOR possible from these pairs is 10 XOR 10 = 0 since the pair (100, 100) also gives 100 XOR 100 = 0.\n
\n\nExample 3:
\n\n\nInput: nums = [5,6,25,30]\nOutput: 7\nExplanation: There are 6 strong pairs in the array nums
: (5, 5), (5, 6), (6, 6), (25, 25), (25, 30) and (30, 30).\nThe maximum XOR possible from these pairs is 25 XOR 30 = 7 since the only other non-zero XOR value is 5 XOR 6 = 3.\n
\n\n\n
Constraints:
\n\n1 <= nums.length <= 50
1 <= nums[i] <= 100
Compiled with clang 11
using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2
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Most standard library headers are already included automatically for your convenience.
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