You are given two 0-indexed integer arrays nums and multipliers of size n and m respectively, where n >= m.
You begin with a score of 0. You want to perform exactly m operations. On the ith operation (0-indexed) you will:
x from either the start or the end of the array nums.multipliers[i] * x to your score.\n multipliers[0] corresponds to the first operation, multipliers[1] to the second operation, and so on.x from nums.Return the maximum score after performing m operations.
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Example 1:
\n\n\nInput: nums = [1,2,3], multipliers = [3,2,1]\nOutput: 14\nExplanation: An optimal solution is as follows:\n- Choose from the end, [1,2,3], adding 3 * 3 = 9 to the score.\n- Choose from the end, [1,2], adding 2 * 2 = 4 to the score.\n- Choose from the end, [1], adding 1 * 1 = 1 to the score.\nThe total score is 9 + 4 + 1 = 14.\n\n
Example 2:
\n\n\nInput: nums = [-5,-3,-3,-2,7,1], multipliers = [-10,-5,3,4,6]\nOutput: 102\nExplanation: An optimal solution is as follows:\n- Choose from the start, [-5,-3,-3,-2,7,1], adding -5 * -10 = 50 to the score.\n- Choose from the start, [-3,-3,-2,7,1], adding -3 * -5 = 15 to the score.\n- Choose from the start, [-3,-2,7,1], adding -3 * 3 = -9 to the score.\n- Choose from the end, [-2,7,1], adding 1 * 4 = 4 to the score.\n- Choose from the end, [-2,7], adding 7 * 6 = 42 to the score. \nThe total score is 50 + 15 - 9 + 4 + 42 = 102.\n\n\n
\n
Constraints:
\n\nn == nums.lengthm == multipliers.length1 <= m <= 300m <= n <= 105 -1000 <= nums[i], multipliers[i] <= 1000Compiled with clang 11 using the latest C++ 20 standard.
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Most standard library headers are already included automatically for your convenience.
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