<p>We have <code>n</code> jobs, where every job is scheduled to be done from <code>startTime[i]</code> to <code>endTime[i]</code>, obtaining a profit of <code>profit[i]</code>.</p> <p>You're given the <code>startTime</code>, <code>endTime</code> and <code>profit</code> arrays, return the maximum profit you can take such that there are no two jobs in the subset with overlapping time range.</p> <p>If you choose a job that ends at time <code>X</code> you will be able to start another job that starts at time <code>X</code>.</p> <p> </p> <p><strong>Example 1:</strong></p> <p><strong><img alt="" src="https://assets.leetcode.com/uploads/2019/10/10/sample1_1584.png" style="width: 380px; height: 154px;" /></strong></p> <pre> <strong>Input:</strong> startTime = [1,2,3,3], endTime = [3,4,5,6], profit = [50,10,40,70] <strong>Output:</strong> 120 <strong>Explanation:</strong> The subset chosen is the first and fourth job. Time range [1-3]+[3-6] , we get profit of 120 = 50 + 70. </pre> <p><strong>Example 2:</strong></p> <p><strong><img alt="" src="https://assets.leetcode.com/uploads/2019/10/10/sample22_1584.png" style="width: 600px; height: 112px;" /> </strong></p> <pre> <strong>Input:</strong> startTime = [1,2,3,4,6], endTime = [3,5,10,6,9], profit = [20,20,100,70,60] <strong>Output:</strong> 150 <strong>Explanation:</strong> The subset chosen is the first, fourth and fifth job. Profit obtained 150 = 20 + 70 + 60. </pre> <p><strong>Example 3:</strong></p> <p><strong><img alt="" src="https://assets.leetcode.com/uploads/2019/10/10/sample3_1584.png" style="width: 400px; height: 112px;" /></strong></p> <pre> <strong>Input:</strong> startTime = [1,1,1], endTime = [2,3,4], profit = [5,6,4] <strong>Output:</strong> 6 </pre> <p> </p> <p><strong>Constraints:</strong></p> <ul> <li><code>1 <= startTime.length == endTime.length == profit.length <= 5 * 10<sup>4</sup></code></li> <li><code>1 <= startTime[i] < endTime[i] <= 10<sup>9</sup></code></li> <li><code>1 <= profit[i] <= 10<sup>4</sup></code></li> </ul>