There are n balls on a table, each ball has a color black or white.
You are given a 0-indexed binary string s of length n, where 1 and 0 represent black and white balls, respectively.
In each step, you can choose two adjacent balls and swap them.
\n\nReturn the minimum number of steps to group all the black balls to the right and all the white balls to the left.
\n\n\n
Example 1:
\n\n\nInput: s = "101"\nOutput: 1\nExplanation: We can group all the black balls to the right in the following way:\n- Swap s[0] and s[1], s = "011".\nInitially, 1s are not grouped together, requiring at least 1 step to group them to the right.\n\n
Example 2:
\n\n\nInput: s = "100"\nOutput: 2\nExplanation: We can group all the black balls to the right in the following way:\n- Swap s[0] and s[1], s = "010".\n- Swap s[1] and s[2], s = "001".\nIt can be proven that the minimum number of steps needed is 2.\n\n\n
Example 3:
\n\n\nInput: s = "0111"\nOutput: 0\nExplanation: All the black balls are already grouped to the right.\n\n\n
\n
Constraints:
\n\n1 <= n == s.length <= 105s[i] is either '0' or '1'.1 in the string s should be swapped with every 0 on its right side.",
"Iterate right to left and count the number of 0 that have already occurred, whenever you iterate on 1 add that counter to the answer."
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