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"content": "<p>Given a <code>m x n</code> binary matrix <code>mat</code>. In one step, you can choose one cell and flip it and all the four neighbors of it if they exist (Flip is changing <code>1</code> to <code>0</code> and <code>0</code> to <code>1</code>). A pair of cells are called neighbors if they share one edge.</p>\n\n<p>Return the <em>minimum number of steps</em> required to convert <code>mat</code> to a zero matrix or <code>-1</code> if you cannot.</p>\n\n<p>A <strong>binary matrix</strong> is a matrix with all cells equal to <code>0</code> or <code>1</code> only.</p>\n\n<p>A <strong>zero matrix</strong> is a matrix with all cells equal to <code>0</code>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/11/28/matrix.png\" style=\"width: 409px; height: 86px;\" />\n<pre>\n<strong>Input:</strong> mat = [[0,0],[0,1]]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> One possible solution is to flip (1, 0) then (0, 1) and finally (1, 1) as shown.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> mat = [[0]]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> Given matrix is a zero matrix. We do not need to change it.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> mat = [[1,0,0],[1,0,0]]\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> Given matrix cannot be a zero matrix.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == mat.length</code></li>\n\t<li><code>n == mat[i].length</code></li>\n\t<li><code>1 <= m, n <= 3</code></li>\n\t<li><code>mat[i][j]</code> is either <code>0</code> or <code>1</code>.</li>\n</ul>\n",
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