{ "data": { "question": { "questionId": "2531", "questionFrontendId": "2440", "boundTopicId": null, "title": "Create Components With Same Value", "titleSlug": "create-components-with-same-value", "content": "
There is an undirected tree with n
nodes labeled from 0
to n - 1
.
You are given a 0-indexed integer array nums
of length n
where nums[i]
represents the value of the ith
node. You are also given a 2D integer array edges
of length n - 1
where edges[i] = [ai, bi]
indicates that there is an edge between nodes ai
and bi
in the tree.
You are allowed to delete some edges, splitting the tree into multiple connected components. Let the value of a component be the sum of all nums[i]
for which node i
is in the component.
Return the maximum number of edges you can delete, such that every connected component in the tree has the same value.
\n\n\n
Example 1:
\n\n\nInput: nums = [6,2,2,2,6], edges = [[0,1],[1,2],[1,3],[3,4]] \nOutput: 2 \nExplanation: The above figure shows how we can delete the edges [0,1] and [3,4]. The created components are nodes [0], [1,2,3] and [4]. The sum of the values in each component equals 6. It can be proven that no better deletion exists, so the answer is 2.\n\n\n
Example 2:
\n\n\nInput: nums = [2], edges = []\nOutput: 0\nExplanation: There are no edges to be deleted.\n\n\n
\n
Constraints:
\n\n1 <= n <= 2 * 104
nums.length == n
1 <= nums[i] <= 50
edges.length == n - 1
edges[i].length == 2
0 <= edges[i][0], edges[i][1] <= n - 1
edges
represents a valid tree.Compiled with clang 11
using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2
). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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Node.js 16.13.2
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Kotlin 1.9.0
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Rust 1.58.1
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