You are given a 0-indexed array nums of size n consisting of non-negative integers.
You need to apply n - 1 operations to this array where, in the ith operation (0-indexed), you will apply the following on the ith element of nums:
nums[i] == nums[i + 1], then multiply nums[i] by 2 and set nums[i + 1] to 0. Otherwise, you skip this operation.After performing all the operations, shift all the 0's to the end of the array.
[1,0,2,0,0,1] after shifting all its 0's to the end, is [1,2,1,0,0,0].Return the resulting array.
\n\nNote that the operations are applied sequentially, not all at once.
\n\n\n
Example 1:
\n\n\nInput: nums = [1,2,2,1,1,0]\nOutput: [1,4,2,0,0,0]\nExplanation: We do the following operations:\n- i = 0: nums[0] and nums[1] are not equal, so we skip this operation.\n- i = 1: nums[1] and nums[2] are equal, we multiply nums[1] by 2 and change nums[2] to 0. The array becomes [1,4,0,1,1,0].\n- i = 2: nums[2] and nums[3] are not equal, so we skip this operation.\n- i = 3: nums[3] and nums[4] are equal, we multiply nums[3] by 2 and change nums[4] to 0. The array becomes [1,4,0,2,0,0].\n- i = 4: nums[4] and nums[5] are equal, we multiply nums[4] by 2 and change nums[5] to 0. The array becomes [1,4,0,2,0,0].\nAfter that, we shift the 0's to the end, which gives the array [1,4,2,0,0,0].\n\n\n
Example 2:
\n\n\nInput: nums = [0,1]\nOutput: [1,0]\nExplanation: No operation can be applied, we just shift the 0 to the end.\n\n\n
\n
Constraints:
\n\n2 <= nums.length <= 20000 <= nums[i] <= 1000Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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