{ "data": { "question": { "questionId": "3203", "questionFrontendId": "2983", "categoryTitle": "Algorithms", "boundTopicId": 2583572, "title": "Palindrome Rearrangement Queries", "titleSlug": "palindrome-rearrangement-queries", "content": "

You are given a 0-indexed string s having an even length n.

\n\n

You are also given a 0-indexed 2D integer array, queries, where queries[i] = [ai, bi, ci, di].

\n\n

For each query i, you are allowed to perform the following operations:

\n\n\n\n

For each query, your task is to determine whether it is possible to make s a palindrome by performing the operations.

\n\n

Each query is answered independently of the others.

\n\n

Return a 0-indexed array answer, where answer[i] == true if it is possible to make s a palindrome by performing operations specified by the ith query, and false otherwise.

\n\n\n\n

 

\n

Example 1:

\n\n
\nInput: s = "abcabc", queries = [[1,1,3,5],[0,2,5,5]]\nOutput: [true,true]\nExplanation: In this example, there are two queries:\nIn the first query:\n- a0 = 1, b0 = 1, c0 = 3, d0 = 5.\n- So, you are allowed to rearrange s[1:1] => abcabc and s[3:5] => abcabc.\n- To make s a palindrome, s[3:5] can be rearranged to become => abccba.\n- Now, s is a palindrome. So, answer[0] = true.\nIn the second query:\n- a1 = 0, b1 = 2, c1 = 5, d1 = 5.\n- So, you are allowed to rearrange s[0:2] => abcabc and s[5:5] => abcabc.\n- To make s a palindrome, s[0:2] can be rearranged to become => cbaabc.\n- Now, s is a palindrome. So, answer[1] = true.\n
\n\n

Example 2:

\n\n
\nInput: s = "abbcdecbba", queries = [[0,2,7,9]]\nOutput: [false]\nExplanation: In this example, there is only one query.\na0 = 0, b0 = 2, c0 = 7, d0 = 9.\nSo, you are allowed to rearrange s[0:2] => abbcdecbba and s[7:9] => abbcdecbba.\nIt is not possible to make s a palindrome by rearranging these substrings because s[3:6] is not a palindrome.\nSo, answer[0] = false.
\n\n

Example 3:

\n\n
\nInput: s = "acbcab", queries = [[1,2,4,5]]\nOutput: [true]\nExplanation: In this example, there is only one query.\na0 = 1, b0 = 2, c0 = 4, d0 = 5.\nSo, you are allowed to rearrange s[1:2] => acbcab and s[4:5] => acbcab.\nTo make s a palindrome s[1:2] can be rearranged to become abccab.\nThen, s[4:5] can be rearranged to become abccba.\nNow, s is a palindrome. So, answer[0] = true.
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "回文串重新排列查询", "translatedContent": "

给你一个长度为 偶数 n ,下标从 0 开始的字符串 s 。

\n\n

同时给你一个下标从 0 开始的二维整数数组 queries ,其中 queries[i] = [ai, bi, ci, di] 。

\n\n

对于每个查询 i ,你需要执行以下操作:

\n\n\n\n

对于每个查询,你的任务是判断执行操作后能否让 s 变成一个 回文串

\n\n

每个查询与其他查询都是 独立的 。

\n\n

请你返回一个下标从 0 开始的数组 answer ,如果第 i 个查询执行操作后,可以将 s 变为一个回文串,那么 answer[i] = true,否则为 false 。

\n\n\n\n

 

\n\n

示例 1:

\n\n
\n输入:s = \"abcabc\", queries = [[1,1,3,5],[0,2,5,5]]\n输出:[true,true]\n解释:这个例子中,有 2 个查询:\n第一个查询:\n- a0 = 1, b0 = 1, c0 = 3, d0 = 5\n- 你可以重新排列 s[1:1] => abcabc 和 s[3:5] => abcabc 。\n- 为了让 s 变为回文串,s[3:5] 可以重新排列得到 => abccba 。\n- 现在 s 是一个回文串。所以 answer[0] = true 。\n第二个查询:\n- a1 = 0, b1 = 2, c1 = 5, d1 = 5.\n- 你可以重新排列 s[0:2] => abcabc 和 s[5:5] => abcabc 。\n- 为了让 s 变为回文串,s[0:2] 可以重新排列得到 => cbaabc 。\n- 现在 s 是一个回文串,所以 answer[1] = true 。\n
\n\n

示例 2:

\n\n
\n输入:s = \"abbcdecbba\", queries = [[0,2,7,9]]\n输出:[false]\n解释:这个示例中,只有一个查询。\na0 = 0, b0 = 2, c0 = 7, d0 = 9.\n你可以重新排列 s[0:2] => abbcdecbba 和 s[7:9] => abbcdecbba 。\n无法通过重新排列这些子字符串使 s 变为一个回文串,因为 s[3:6] 不是一个回文串。\n所以 answer[0] = false 。
\n\n

示例 3:

\n\n
\n输入:s = \"acbcab\", queries = [[1,2,4,5]]\n输出:[true]\n解释:这个示例中,只有一个查询。\na0 = 1, b0 = 2, c0 = 4, d0 = 5.\n你可以重新排列 s[1:2] => acbcab 和 s[4:5] => acbcab 。\n为了让 s 变为回文串,s[1:2] 可以重新排列得到 => abccab 。\n然后 s[4:5] 重新排列得到 abccba 。\n现在 s 是一个回文串,所以 answer[0] = true 。
\n\n

 

\n\n

提示:

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Racket CS<\\/a> v8.11<\\/p>\\r\\n\\r\\n

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Dart 3.2<\\/p>\\r\\n\\r\\n

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