{ "data": { "question": { "questionId": "3500", "questionFrontendId": "3219", "categoryTitle": "Algorithms", "boundTopicId": 2840440, "title": "Minimum Cost for Cutting Cake II", "titleSlug": "minimum-cost-for-cutting-cake-ii", "content": "
There is an m x n
cake that needs to be cut into 1 x 1
pieces.
You are given integers m
, n
, and two arrays:
horizontalCut
of size m - 1
, where horizontalCut[i]
represents the cost to cut along the horizontal line i
.verticalCut
of size n - 1
, where verticalCut[j]
represents the cost to cut along the vertical line j
.In one operation, you can choose any piece of cake that is not yet a 1 x 1
square and perform one of the following cuts:
i
at a cost of horizontalCut[i]
.j
at a cost of verticalCut[j]
.After the cut, the piece of cake is divided into two distinct pieces.
\n\nThe cost of a cut depends only on the initial cost of the line and does not change.
\n\nReturn the minimum total cost to cut the entire cake into 1 x 1
pieces.
\n
Example 1:
\n\nInput: m = 3, n = 2, horizontalCut = [1,3], verticalCut = [5]
\n\nOutput: 13
\n\nExplanation:
\n\n\n\n3 x 1
subgrid with cost 1.3 x 1
subgrid with cost 1.2 x 1
subgrid with cost 3.2 x 1
subgrid with cost 3.The total cost is 5 + 1 + 1 + 3 + 3 = 13
.
Example 2:
\n\nInput: m = 2, n = 2, horizontalCut = [7], verticalCut = [4]
\n\nOutput: 15
\n\nExplanation:
\n\n1 x 2
subgrid with cost 4.1 x 2
subgrid with cost 4.The total cost is 7 + 4 + 4 = 15
.
\n
Constraints:
\n\n1 <= m, n <= 105
horizontalCut.length == m - 1
verticalCut.length == n - 1
1 <= horizontalCut[i], verticalCut[i] <= 103
有一个 m x n
大小的矩形蛋糕,需要切成 1 x 1
的小块。
给你整数 m
,n
和两个数组:
horizontalCut
的大小为 m - 1
,其中 horizontalCut[i]
表示沿着水平线 i
切蛋糕的开销。verticalCut
的大小为 n - 1
,其中 verticalCut[j]
表示沿着垂直线 j
切蛋糕的开销。一次操作中,你可以选择任意不是 1 x 1
大小的矩形蛋糕并执行以下操作之一:
i
切开蛋糕,开销为 horizontalCut[i]
。j
切开蛋糕,开销为 verticalCut[j]
。每次操作后,这块蛋糕都被切成两个独立的小蛋糕。
\n\n每次操作的开销都为最开始对应切割线的开销,并且不会改变。
\n\n请你返回将蛋糕全部切成 1 x 1
的蛋糕块的 最小 总开销。
\n\n
示例 1:
\n\n输入:m = 3, n = 2, horizontalCut = [1,3], verticalCut = [5]
\n\n输出:13
\n\n解释:
\n\n\n\n3 x 1
的蛋糕块,开销为 1 。3 x 1
的蛋糕块,开销为 1 。2 x 1
的蛋糕块,开销为 3 。2 x 1
的蛋糕块,开销为 3 。总开销为 5 + 1 + 1 + 3 + 3 = 13
。
示例 2:
\n\n输入:m = 2, n = 2, horizontalCut = [7], verticalCut = [4]
\n\n输出:15
\n\n解释:
\n\n1 x 2
的蛋糕块,开销为 4 。1 x 2
的蛋糕块,开销为 4 。总开销为 7 + 4 + 4 = 15
。
\n\n
提示:
\n\n1 <= m, n <= 105
horizontalCut.length == m - 1
verticalCut.length == n - 1
1 <= horizontalCut[i], verticalCut[i] <= 103
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