You are given a 0-indexed integer array nums. A pair of integers x and y is called a strong pair if it satisfies the condition:
|x - y| <= min(x, y)You need to select two integers from nums such that they form a strong pair and their bitwise XOR is the maximum among all strong pairs in the array.
Return the maximum XOR value out of all possible strong pairs in the array nums.
Note that you can pick the same integer twice to form a pair.
\n\n\n
Example 1:
\n\n\nInput: nums = [1,2,3,4,5]\nOutput: 7\nExplanation: There are 11 strong pairs in the array nums: (1, 1), (1, 2), (2, 2), (2, 3), (2, 4), (3, 3), (3, 4), (3, 5), (4, 4), (4, 5) and (5, 5).\nThe maximum XOR possible from these pairs is 3 XOR 4 = 7.\n\n\nExample 2:
\n\n\nInput: nums = [10,100]\nOutput: 0\nExplanation: There are 2 strong pairs in the array nums: (10, 10) and (100, 100).\nThe maximum XOR possible from these pairs is 10 XOR 10 = 0 since the pair (100, 100) also gives 100 XOR 100 = 0.\n\n\n
Example 3:
\n\n\nInput: nums = [500,520,2500,3000]\nOutput: 1020\nExplanation: There are 6 strong pairs in the array nums: (500, 500), (500, 520), (520, 520), (2500, 2500), (2500, 3000) and (3000, 3000).\nThe maximum XOR possible from these pairs is 500 XOR 520 = 1020 since the only other non-zero XOR value is 2500 XOR 3000 = 636.\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 5 * 1041 <= nums[i] <= 220 - 1给你一个下标从 0 开始的整数数组 nums 。如果一对整数 x 和 y 满足以下条件，则称其为 强数对 ：
|x - y| <= min(x, y)你需要从 nums 中选出两个整数，且满足：这两个整数可以形成一个强数对，并且它们的按位异或（XOR）值是在该数组所有强数对中的 最大值 。
返回数组 nums 所有可能的强数对中的 最大 异或值。
注意，你可以选择同一个整数两次来形成一个强数对。
\n\n\n\n
示例 1：
\n\n\n输入：nums = [1,2,3,4,5]\n输出：7\n解释：数组 nums 中有 11 个强数对：(1, 1), (1, 2), (2, 2), (2, 3), (2, 4), (3, 3), (3, 4), (3, 5), (4, 4), (4, 5) 和 (5, 5) 。\n这些强数对中的最大异或值是 3 XOR 4 = 7 。\n\n\n示例 2：
\n\n\n输入：nums = [10,100]\n输出：0\n解释：数组 nums 中有 2 个强数对：(10, 10) 和 (100, 100) 。\n这些强数对中的最大异或值是 10 XOR 10 = 0 ，数对 (100, 100) 的异或值也是 100 XOR 100 = 0 。\n\n\n示例 3：
\n\n\n输入：nums = [500,520,2500,3000]\n输出：1020\n解释：数组 nums 中有 6 个强数对：(500, 500), (500, 520), (520, 520), (2500, 2500), (2500, 3000) 和 (3000, 3000) 。\n这些强数对中的最大异或值是 500 XOR 520 = 1020 ；另一个异或值非零的数对是 (5, 6) ，其异或值是 2500 XOR 3000 = 636 。\n\n\n\n\n
提示：
\n\n1 <= nums.length <= 5 * 1041 <= nums[i] <= 220 - 1x <= y which means |x - y| <= min(x, y) can now be written as y - x <= x or in other words, y <= 2 * x.",
"If x and y have the same number of bits, try makingy’s bits different from x if possible for each bit starting from the second most significant bit.",
"If y has 1 more bit than x and y <= 2 * x use the idea about Digit DP to make y’s prefix smaller than 2 * x + 1 as well as trying to make each bit different from x using a Hashmap.",
"Alternatively, use Trie data structure to find the pair with maximum XOR."
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