{ "data": { "question": { "questionId": "100347", "questionFrontendId": "LCR 194", "categoryTitle": "Algorithms", "boundTopicId": 88799, "title": "寻找二叉树的最近公共祖先", "titleSlug": "er-cha-shu-de-zui-jin-gong-gong-zu-xian-lcof", "content": "

English description is not available for the problem. Please switch to Chinese.

\r\n", "translatedTitle": "二叉树的最近公共祖先", "translatedContent": "

给定一个二叉树, 找到该树中两个指定节点的最近公共祖先。

\n\n

百度百科中最近公共祖先的定义为：“对于有根树 T 的两个结点 p、q，最近公共祖先表示为一个结点 x，满足 x 是 p、q 的祖先且 x 的深度尽可能大（一个节点也可以是它自己的祖先）。”

\n\n

例如，给定如下二叉树:  root = [3,5,1,6,2,0,8,null,null,7,4]

\n\n

\"\"

\n\n

 

\n\n

示例 1:

\n\n
输入: root = [3,5,1,6,2,0,8,null,null,7,4], p = 5, q = 1\n输出: 3\n解释: 节点 5 和节点 1 的最近公共祖先是节点 3。\n
\n\n

示例 2:

\n\n
输入: root = [3,5,1,6,2,0,8,null,null,7,4], p = 5, q = 4\n输出: 5\n解释: 节点 5 和节点 4 的最近公共祖先是节点 5。因为根据定义最近公共祖先节点可以为节点本身。\n
\n\n

 

\n\n

说明:

\n\n\n\n

注意：本题与主站 236 题相同：https://leetcode-cn.com/problems/lowest-common-ancestor-of-a-binary-tree/

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