{ "data": { "question": { "questionId": "2732", "questionFrontendId": "2620", "categoryTitle": "JavaScript", "boundTopicId": 2222282, "title": "Counter", "titleSlug": "counter", "content": "

Given an integer n, return a counter function. This counter function initially returns n and then returns 1 more than the previous value every subsequent time it is called (n, n + 1, n + 2, etc).

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Example 1:

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\nInput: \nn = 10 \n["call","call","call"]\nOutput: [10,11,12]\nExplanation: \ncounter() = 10 // The first time counter() is called, it returns n.\ncounter() = 11 // Returns 1 more than the previous time.\ncounter() = 12 // Returns 1 more than the previous time.\n
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Example 2:

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\nInput: \nn = -2\n["call","call","call","call","call"]\nOutput: [-2,-1,0,1,2]\nExplanation: counter() initially returns -2. Then increases after each sebsequent call.\n
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Constraints:

\n\n\n", "translatedTitle": "计数器", "translatedContent": "

给定一个整型参数 n，请你编写并返回一个 counter 函数。这个 counter 函数最初返回 n，每次调用它时会返回前一个值加 1 的值 ( n ,  n + 1 ,  n + 2 ，等等)。

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示例 1：

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\n输入：\nn = 10 \n[\"call\",\"call\",\"call\"]\n输出：[10,11,12]\n解释：\ncounter() = 10 // 第一次调用 counter()，返回 n。\ncounter() = 11 // 返回上次调用的值加 1。\ncounter() = 12 // 返回上次调用的值加 1。\n
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示例 2：

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\n输入：\nn = -2\n[\"call\",\"call\",\"call\",\"call\",\"call\"]\n输出：[-2,-1,0,1,2]\n解释：counter() 最初返回 -2。然后在每个后续调用后增加 1。\n
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提示：

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