You are given two positive integers left and right with left <= right. Calculate the product of all integers in the inclusive range [left, right].
Since the product may be very large, you will abbreviate it following these steps:
\n\nC.\n\n\t3 trailing zeros in 1000, and there are 0 trailing zeros in 546.d. If d > 10, then express the product as <pre>...<suf> where <pre> denotes the first 5 digits of the product, and <suf> denotes the last 5 digits of the product after removing all trailing zeros. If d <= 10, we keep it unchanged.\n\t1234567654321 as 12345...54321, but 1234567 is represented as 1234567."<pre>...<suf>eC".\n\t12345678987600000 will be represented as "12345...89876e5".Return a string denoting the abbreviated product of all integers in the inclusive range [left, right].
\n
Example 1:
\n\n\nInput: left = 1, right = 4\nOutput: "24e0"\nExplanation: The product is 1 × 2 × 3 × 4 = 24.\nThere are no trailing zeros, so 24 remains the same. The abbreviation will end with "e0".\nSince the number of digits is 2, which is less than 10, we do not have to abbreviate it further.\nThus, the final representation is "24e0".\n\n\n
Example 2:
\n\n\nInput: left = 2, right = 11\nOutput: "399168e2"\nExplanation: The product is 39916800.\nThere are 2 trailing zeros, which we remove to get 399168. The abbreviation will end with "e2".\nThe number of digits after removing the trailing zeros is 6, so we do not abbreviate it further.\nHence, the abbreviated product is "399168e2".\n\n\n
Example 3:
\n\n\nInput: left = 371, right = 375\nOutput: "7219856259e3"\nExplanation: The product is 7219856259000.\n\n\n
\n
Constraints:
\n\n1 <= left <= right <= 104给你两个正整数 left 和 right ，满足 left <= right 。请你计算 闭区间 [left, right] 中所有整数的 乘积 。
由于乘积可能非常大，你需要将它按照以下步骤 缩写 ：
\n\nC 。\n\n\t1000 中有 3 个后缀 0 ，546 中没有后缀 0 。d 。如果 d > 10 ，那么将乘积表示为 <pre>...<suf> 的形式，其中 <pre> 表示乘积最 开始 的 5 个数位，<suf> 表示删除后缀 0 之后 结尾的 5 个数位。如果 d <= 10 ，我们不对它做修改。\n\t1234567654321 表示为 12345...54321 ，但是 1234567 仍然表示为 1234567 。\"<pre>...<suf>eC\" 。\n\t12345678987600000 被表示为 \"12345...89876e5\" 。请你返回一个字符串，表示 闭区间 [left, right] 中所有整数 乘积 的 缩写 。
\n\n
示例 1：
\n\n\n输入：left = 1, right = 4\n输出：\"24e0\"\n解释：\n乘积为 1 × 2 × 3 × 4 = 24 。\n由于没有后缀 0 ，所以 24 保持不变，缩写的结尾为 \"e0\" 。\n因为乘积的结果是 2 位数，小于 10 ，所欲我们不进一步将它缩写。\n所以，最终将乘积表示为 \"24e0\" 。\n\n\n
示例 2：
\n\n\n输入：left = 2, right = 11\n输出：\"399168e2\"\n解释：乘积为 39916800 。\n有 2 个后缀 0 ，删除后得到 399168 。缩写的结尾为 \"e2\" 。 \n删除后缀 0 后是 6 位数，不需要进一步缩写。 \n所以，最终将乘积表示为 \"399168e2\" 。\n\n\n
示例 3：
\n\n\n输入：left = 371, right = 375\n输出：\"7219856259e3\"\n解释：乘积为 7219856259000 。\n\n\n
\n\n
提示：
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collections<\\/a>\\u3002\\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u6ce8\\u610f Python 2.7 \\u5c06\\u57282020\\u5e74\\u540e\\u4e0d\\u518d\\u7ef4\\u62a4<\\/a>\\u3002 \\u5982\\u60f3\\u4f7f\\u7528\\u6700\\u65b0\\u7248\\u7684Python\\uff0c\\u8bf7\\u9009\\u62e9Python 3\\u3002<\\/p>\"],\"c\":[\"C\",\" \\u7248\\u672c\\uff1a \\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528 \\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u5982\\u60f3\\u4f7f\\u7528\\u54c8\\u5e0c\\u8868\\u8fd0\\u7b97, \\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 uthash<\\/a>\\u3002 \\\"uthash.h\\\"\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5bfc\\u5165\\u3002\\u8bf7\\u770b\\u5982\\u4e0b\\u793a\\u4f8b:<\\/p>\\r\\n\\r\\n 1. 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