{ "data": { "question": { "questionId": "1000265", "questionFrontendId": "LCR 029", "categoryTitle": "Algorithms", "boundTopicId": 910265, "title": "循环有序列表的插入", "titleSlug": "4ueAj6", "content": "
English description is not available for the problem. Please switch to Chinese.
\n", "translatedTitle": "循环有序列表的插入", "translatedContent": "给定循环单调非递减列表中的一个点,写一个函数向这个列表中插入一个新元素 insertVal
,使这个列表仍然是循环升序的。
给定的可以是这个列表中任意一个顶点的指针,并不一定是这个列表中最小元素的指针。
\n\n如果有多个满足条件的插入位置,可以选择任意一个位置插入新的值,插入后整个列表仍然保持有序。
\n\n如果列表为空(给定的节点是 null
),需要创建一个循环有序列表并返回这个节点。否则。请返回原先给定的节点。
\n\n
示例 1:
\n\n
\n
\n输入:head = [3,4,1], insertVal = 2\n输出:[3,4,1,2]\n解释:在上图中,有一个包含三个元素的循环有序列表,你获得值为 3 的节点的指针,我们需要向表中插入元素 2 。新插入的节点应该在 1 和 3 之间,插入之后,整个列表如上图所示,最后返回节点 3 。\n\n\n\n\n
示例 2:
\n\n\n输入:head = [], insertVal = 1\n输出:[1]\n解释:列表为空(给定的节点是 null
),创建一个循环有序列表并返回这个节点。\n
\n\n示例 3:
\n\n\n输入:head = [1], insertVal = 0\n输出:[1,0]\n\n\n
\n\n
提示:
\n\n0 <= Number of Nodes <= 5 * 10^4
-10^6 <= Node.val <= 10^6
-10^6 <= insertVal <= 10^6
\n\n
注意:本题与主站 708 题相同: https://leetcode-cn.com/problems/insert-into-a-sorted-circular-linked-list/
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__init__(self, val=None, next=None):\n self.val = val\n self.next = next\n\"\"\"\n\nclass Solution(object):\n def insert(self, head, insertVal):\n \"\"\"\n :type head: Node\n :type insertVal: int\n :rtype: Node\n \"\"\"\n\t\t", "__typename": "CodeSnippetNode" }, { "lang": "Python3", "langSlug": "python3", "code": "\"\"\"\n# Definition for a Node.\nclass Node:\n def __init__(self, val=None, next=None):\n self.val = val\n self.next = next\n\"\"\"\n\nclass Solution:\n def insert(self, head: 'Node', insertVal: int) -> 'Node':\n ", "__typename": "CodeSnippetNode" }, { "lang": "C", "langSlug": "c", "code": "/**\n * Definition for a Node.\n * struct Node {\n * int val;\n * struct TreeNode *next;\n * };\n */\n\nstruct Node* insert(struct Node* head, int insertVal) {\n \n}", "__typename": "CodeSnippetNode" }, { "lang": "C#", "langSlug": "csharp", "code": "/*\n// Definition for a Node.\npublic class Node {\n public int val;\n public Node next;\n\n public Node() {}\n\n public Node(int _val) {\n 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