You are given an integer array nums that represents a circular array. Your task is to create a new array result of the same size, following these rules:
i (where 0 <= i < nums.length), perform the following independent actions:\n\nnums[i] > 0: Start at index i and move nums[i] steps to the right in the circular array. Set result[i] to the value of the index where you land.nums[i] < 0: Start at index i and move abs(nums[i]) steps to the left in the circular array. Set result[i] to the value of the index where you land.nums[i] == 0: Set result[i] to nums[i].Return the new array result.
Note: Since nums is circular, moving past the last element wraps around to the beginning, and moving before the first element wraps back to the end.
\n
Example 1:
\n\nInput: nums = [3,-2,1,1]
\n\nOutput: [1,1,1,3]
\n\nExplanation:
\n\nnums[0] that is equal to 3, If we move 3 steps to right, we reach nums[3]. So result[0] should be 1.nums[1] that is equal to -2, If we move 2 steps to left, we reach nums[3]. So result[1] should be 1.nums[2] that is equal to 1, If we move 1 step to right, we reach nums[3]. So result[2] should be 1.nums[3] that is equal to 1, If we move 1 step to right, we reach nums[0]. So result[3] should be 3.Example 2:
\n\nInput: nums = [-1,4,-1]
\n\nOutput: [-1,-1,4]
\n\nExplanation:
\n\nnums[0] that is equal to -1, If we move 1 step to left, we reach nums[2]. So result[0] should be -1.nums[1] that is equal to 4, If we move 4 steps to right, we reach nums[2]. So result[1] should be -1.nums[2] that is equal to -1, If we move 1 step to left, we reach nums[1]. So result[2] should be 4.\n
Constraints:
\n\n1 <= nums.length <= 100-100 <= nums[i] <= 100Compiled with clang 19 using the latest C++ 23 standard, and libstdc++ provided by GCC 14.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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