You are given a 1-indexed array of distinct integers nums of length n.
You need to distribute all the elements of nums between two arrays arr1 and arr2 using n operations. In the first operation, append nums[1] to arr1. In the second operation, append nums[2] to arr2. Afterwards, in the ith operation:
arr1 is greater than the last element of arr2, append nums[i] to arr1. Otherwise, append nums[i] to arr2.The array result is formed by concatenating the arrays arr1 and arr2. For example, if arr1 == [1,2,3] and arr2 == [4,5,6], then result = [1,2,3,4,5,6].
Return the array result.
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Example 1:
\n\n\nInput: nums = [2,1,3]\nOutput: [2,3,1]\nExplanation: After the first 2 operations, arr1 = [2] and arr2 = [1].\nIn the 3rd operation, as the last element of arr1 is greater than the last element of arr2 (2 > 1), append nums[3] to arr1.\nAfter 3 operations, arr1 = [2,3] and arr2 = [1].\nHence, the array result formed by concatenation is [2,3,1].\n\n\n
Example 2:
\n\n\nInput: nums = [5,4,3,8]\nOutput: [5,3,4,8]\nExplanation: After the first 2 operations, arr1 = [5] and arr2 = [4].\nIn the 3rd operation, as the last element of arr1 is greater than the last element of arr2 (5 > 4), append nums[3] to arr1, hence arr1 becomes [5,3].\nIn the 4th operation, as the last element of arr2 is greater than the last element of arr1 (4 > 3), append nums[4] to arr2, hence arr2 becomes [4,8].\nAfter 4 operations, arr1 = [5,3] and arr2 = [4,8].\nHence, the array result formed by concatenation is [5,3,4,8].\n\n\n
\n
Constraints:
\n\n3 <= n <= 501 <= nums[i] <= 100nums are distinct.Compiled with clang 17 using the latest C++ 20 standard, and libstdc++ provided by GCC 11.
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