{ "data": { "question": { "questionId": "1023", "questionFrontendId": "981", "categoryTitle": "Algorithms", "boundTopicId": 2910, "title": "Time Based Key-Value Store", "titleSlug": "time-based-key-value-store", "content": "
Design a time-based key-value data structure that can store multiple values for the same key at different time stamps and retrieve the key's value at a certain timestamp.
\n\nImplement the TimeMap class:
TimeMap() Initializes the object of the data structure.void set(String key, String value, int timestamp) Stores the key key with the value value at the given time timestamp.String get(String key, int timestamp) Returns a value such that set was called previously, with timestamp_prev <= timestamp. If there are multiple such values, it returns the value associated with the largest timestamp_prev. If there are no values, it returns "".\n
Example 1:
\n\n\nInput\n["TimeMap", "set", "get", "get", "set", "get", "get"]\n[[], ["foo", "bar", 1], ["foo", 1], ["foo", 3], ["foo", "bar2", 4], ["foo", 4], ["foo", 5]]\nOutput\n[null, null, "bar", "bar", null, "bar2", "bar2"]\n\nExplanation\nTimeMap timeMap = new TimeMap();\ntimeMap.set("foo", "bar", 1); // store the key "foo" and value "bar" along with timestamp = 1.\ntimeMap.get("foo", 1); // return "bar"\ntimeMap.get("foo", 3); // return "bar", since there is no value corresponding to foo at timestamp 3 and timestamp 2, then the only value is at timestamp 1 is "bar".\ntimeMap.set("foo", "bar2", 4); // store the key "foo" and value "bar2" along with timestamp = 4.\ntimeMap.get("foo", 4); // return "bar2"\ntimeMap.get("foo", 5); // return "bar2"\n\n\n\n
Constraints:
\n\n1 <= key.length, value.length <= 100key and value consist of lowercase English letters and digits.1 <= timestamp <= 107timestamp of set are strictly increasing.2 * 105 calls will be made to set and get.设计一个基于时间的键值数据结构,该结构可以在不同时间戳存储对应同一个键的多个值,并针对特定时间戳检索键对应的值。
\n\n实现 TimeMap 类:
TimeMap() 初始化数据结构对象void set(String key, String value, int timestamp) 存储给定时间戳 timestamp 时的键 key 和值 value。String get(String key, int timestamp) 返回一个值,该值在之前调用了 set,其中 timestamp_prev <= timestamp 。如果有多个这样的值,它将返回与最大 timestamp_prev 关联的值。如果没有值,则返回空字符串(\"\")。示例 1:
\n\n\n输入:\n[\"TimeMap\", \"set\", \"get\", \"get\", \"set\", \"get\", \"get\"]\n[[], [\"foo\", \"bar\", 1], [\"foo\", 1], [\"foo\", 3], [\"foo\", \"bar2\", 4], [\"foo\", 4], [\"foo\", 5]]\n输出:\n[null, null, \"bar\", \"bar\", null, \"bar2\", \"bar2\"]\n\n解释:\nTimeMap timeMap = new TimeMap();\ntimeMap.set(\"foo\", \"bar\", 1); // 存储键 \"foo\" 和值 \"bar\" ,时间戳 timestamp = 1 \ntimeMap.get(\"foo\", 1); // 返回 \"bar\"\ntimeMap.get(\"foo\", 3); // 返回 \"bar\", 因为在时间戳 3 和时间戳 2 处没有对应 \"foo\" 的值,所以唯一的值位于时间戳 1 处(即 \"bar\") 。\ntimeMap.set(\"foo\", \"bar2\", 4); // 存储键 \"foo\" 和值 \"bar2\" ,时间戳 timestamp = 4 \ntimeMap.get(\"foo\", 4); // 返回 \"bar2\"\ntimeMap.get(\"foo\", 5); // 返回 \"bar2\"\n\n\n
\n\n
提示:
\n\n1 <= key.length, value.length <= 100key 和 value 由小写英文字母和数字组成1 <= timestamp <= 107set 操作中的时间戳 timestamp 都是严格递增的set 和 get 操作 2 * 105 次\\u7248\\u672c\\uff1a \\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528 \\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\"],\"java\":[\"Java\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u88ab\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u5305\\u542b Pair \\u7c7b: https:\\/\\/docs.oracle.com\\/javase\\/8\\/javafx\\/api\\/javafx\\/util\\/Pair.html <\\/p>\"],\"python\":[\"Python\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982\\uff1aarray<\\/a>, bisect<\\/a>, 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{\\r\\n HASH_ADD_INT(users, id, s);\\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\\r\\n\\r\\n\\r\\nstruct hash_entry *find_user(int user_id) {\\r\\n struct hash_entry *s;\\r\\n HASH_FIND_INT(users, &user_id, s);\\r\\n return s;\\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\\r\\n\\r\\n\\r\\nvoid delete_user(struct hash_entry *user) {\\r\\n HASH_DEL(users, user); \\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\"],\"csharp\":[\"C#\",\"Node.js 22.14.0<\\/code><\\/p>\\r\\n\\r\\n--harmony<\\/code> \\u6807\\u8bb0\\u6765\\u5f00\\u542f \\u65b0\\u7248ES6\\u7279\\u6027<\\/a>\\u3002<\\/p>\\r\\n\\r\\nRuby 3.2<\\/code> \\u6267\\u884c<\\/p>\\r\\n\\r\\nSwift 6.0<\\/code><\\/p>\\r\\n\\r\\nGo 1.23<\\/code><\\/p>\\r\\n\\r\\nPython 3.11<\\/code><\\/p>\\r\\n\\r\\nScala 3.3.1<\\/code><\\/p>\"],\"kotlin\":[\"Kotlin\",\"Kotlin 2.1.10<\\/code><\\/p>\"],\"rust\":[\"Rust\",\"rust 1.88.0<\\/code>\\uff0c\\u4f7f\\u7528 edition 2024\\u3002<\\/p>\\r\\n\\r\\nPHP 8.2<\\/code>.<\\/p>\\r\\n\\r\\n-O2 --disable-reflection<\\/code><\\/p>\\r\\n\\r\\n